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Is |x| < 1 ? (1) |x + 1| = 2|x 1| (2) |x 3| > 0 What

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Is |x| < 1 ? (1) |x + 1| = 2|x 1| (2) |x 3| > 0 What [#permalink] New post 28 Jul 2008, 13:40
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Is |x| < 1 ?

(1) |x + 1| = 2|x – 1|
(2) |x – 3| > 0

What should be the best way to solve this ?

Thanks,
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Joined: 28 Dec 2004
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Schools: Wharton'11 HBS'12
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Re: DS - Mod Inequality [#permalink] New post 28 Jul 2008, 13:46
KumarGMAT wrote:
Is |x| < 1 ?

(1) |x + 1| = 2|x – 1|
(2) |x – 3| > 0

What should be the best way to solve this ?

Thanks,


lets

if x>1

x+1=2x-2
3=x OK works

if 0<x<1
x+1=-2(x-1)
x+1=-2x+2
3x=1 x=1/3 works..

if x<0

-(x+1)=-2(x-1)
-x-1=-2x+1
x=0 ..not possible since x<0

so 1) is insuff
look at 2) again insuff

but 1+2) |x-3|>0 means x is not equal to 3..therefore x=1/3 sufficient C

this i would rate as 450 level question..
Re: DS - Mod Inequality   [#permalink] 28 Jul 2008, 13:46
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