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bkk, do you think you could show me how in (1) you solved x=3 or x=1/3? I'm not too great with abs values. Thanks!
Sure, you have |x+1| = 2*|x-1| You know that |x+1| is positive when x>-1 and negative when x<-1 |x-1| is positive when x>1 and negative when x<1 This means that in a number line, the intervals you have are: x<-1, -1<x<1, x>1
Now, solve the equation according to those intervals: For x<-1, -x-1 = 2*(-x+1) -x-1 = -2x+2 x = 3
For -1<x<1, x+1 = 2*(-x+1) x+1 = -2x+2 x = 1/3
For x>1 x+1 = 2*(x-1) x+1 = 2x-2 x = 3
x equals to 3 or 1/3
I know, all these signs are confusing! I attached a document for you, take a look. It helped me.