ywilfred wrote:

1) x^3>x

x^3-x > 0

x(x^2-1)>0

x(x-1)(x+1)>0

The inequality:

-1 < x < 0

x > 1

Insufficient as we do not know which range x falls into.

2) x^2 > x > 0

- We know x must be positive

- We know x^2 must be greater than x, so x cannot be a positive fraction (e.g. 1/2)

- We know x cannot be 1 as well since this will result in x^2 = x

Sufficient.

Ans B

Wilfred & girish,

I got how you treated first condition but I have a different view here.

x^3 > x

Without solving it, if we plug & play in this equation, we easily get the range of x i.e. x>1

Reason:

1) For x < 0

x^3 < x, if x = -3, x^3 = -27

2) For 0 < x < 1

x^3 < x, if x = 0.2, x^3 = 0.008

3) For x > 1

x^3 > x, if x = 3, x^3 = 27

The only range that satisfies x^3 > x, is x > 1.

Am I missing something?