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The product of 3 numbers is positive if all three are positive (+++) OR two of them are negative and the third one is positive (+--).

Note that: out of 3 numbers \(x-3\) is the least one and \(x-1\) is the biggest one.

\((+)(+)(+)\) is when even the least one is positive so when \(x-3>0\) --> \(x>3\); \((+)(-)(-)\) is when the biggest one is positive (\(x-1>0\) --> \(x>1\)) and the next one (hence the leas one too) negative (\(x-2<0\) --> x<2), so when \(1<x<2\);

So \((x-3)(x-2)(x-1)>0\) means that: \(x>3\) or \(1<x<2\) --> \(x\) may or may not be more than 3. Not sufficient.

(2) \(x>1\). Clearly insufficient.

(1)+(2) Intersection of the ranges from (1) and (2) is the range we had in (1) \(x>3\) or \(1<x<2\), so \(x\) may or may not be more than 3. Not sufficient.

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