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Is x > 0

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Is x > 0 [#permalink]

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New post 24 Jan 2011, 06:42
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Is x > 0

(1) x < x^2
(2) x^2 < x^3
[Reveal] Spoiler: OA

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Re: One more Algebra DS [#permalink]

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New post 24 Jan 2011, 06:59
(1) If x = 2, then \(x^2 = 4\); here x > 0
If x = -2, then \(x^2 = (-2)^2 = 4\); here x < 0
x may or may not be greater than 0. Hence, there is no unique answer.
So, statement 1 is NOT SUFFICIENT.

(2) \(x^2 < x^3\) implies that x > 1, which implies x is always positive. So, x > 0.
So, statement 2 is SUFFICIENT.

[Reveal] Spoiler:
The correct answer is B.

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Re: One more Algebra DS [#permalink]

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New post 24 Jan 2011, 07:37
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Re: One more Algebra DS [#permalink]

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New post 17 Mar 2011, 22:56
Very easy. Question asks if x is positive ...fraction OR integer doesn't matter..
Statement 1 says that x is either a negative fraction OR a positive integer.
Statement 2 says that x is definitely a positive integer.
Hence B
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Re: One more Algebra DS [#permalink]

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New post 18 Mar 2011, 00:09
(1)

x-x^2 < 0

x(1-x) < 0

=> x > 1 or x < 0, so not sufficient

(2)
x^2 < x^3

=> x is +ve as if x is -ve then, then x^3 will be -ve while x^2 will be still +ve and +ve can't be < -ve

Answer B.
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Re: Is x > 0 [#permalink]

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New post 09 Oct 2014, 09:13
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Is x > 0   [#permalink] 09 Oct 2014, 09:13
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