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Is x^2 + 2*a*x + (3+a^2) > x ? (1) a > 2 (2) x &#8804;

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Manager
Joined: 02 Jul 2004
Posts: 218
Followers: 1

Kudos [?]: 2 [0], given: 0

Is x^2 + 2*a*x + (3+a^2) > x ? (1) a > 2 (2) x &#8804; [#permalink]  10 Aug 2004, 04:45
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is x^2 + 2*a*x + (3+a^2) > x ?

(1) a > â€“2
(2) x ≤ 3
Senior Manager
Joined: 22 Jun 2004
Posts: 394
Location: Bangalore, India
Followers: 1

Kudos [?]: 2 [0], given: 0

Re: DS - difficulty 6 out of 10 [#permalink]  10 Aug 2004, 06:06
I got it as A.

(1)Substitution of different values of a in the eq gives a definitive +ve trend. So, +ve. Thus, sufficient.
(2)
Take x as +3 and -3 and substitute different values of a. We get both yes and no as answers. hence insufficient.

OlegC wrote:
Is x^2 + 2*a*x + (3+a^2) > x ?

(1) a > â€“2
(2) x ≤ 3

_________________

Awaiting response,

Thnx & Rgds,
Chandra

Intern
Joined: 16 Aug 2004
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

The answer is E. Because 1) does not give a decisive answer, if we select (-1) as the value of 'a', the inequation simplifies to
Is (x-2)^2 > x ?
This is not always true:
for x=2 , it is not true
for x=-2, it is true
for x=4 , it is not true ; etc.
Manager
Joined: 02 Jul 2004
Posts: 218
Followers: 1

Kudos [?]: 2 [0], given: 0

sorry, I forgot to post the OA

the OA is A
explanation attched
Attachments

explanation.doc [19.5 KiB]

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