Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2 : DS Archive
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# Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2

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Manager
Joined: 01 Nov 2005
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Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2 [#permalink]

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19 Nov 2005, 09:19
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100% (01:50) correct 0% (00:00) wrong based on 2 sessions

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Is X^2+Y^2 > 6?

1. (x+y)^2 > 6
2. xy = 2
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Joined: 24 Sep 2005
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Kudos [?]: 292 [0], given: 0

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19 Nov 2005, 09:31
imaru wrote:
Is X^2+Y^2 > 6?

1. (x+y)^2 > 6
2. xy = 2

1. we have x^2+y^2> [(x+y)^2]/2 >6/2=3 , can't conclude if x^2+y^2>6 ---> insuff

2. we have x^2+y^2>2xy=4 , can't conclude if x^2+y^2> 6 ---> insuff

1 and 2
(x+y)^2= x^2+ y^2 + 2xy>6, xy= 2 ---> x^2+y^2>6-4=2 ---> cant conclude if x^2+y^2> 6 ---> insuff.
Re: DS   [#permalink] 19 Nov 2005, 09:31
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# Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2

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