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Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2

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Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2 [#permalink] New post 19 Nov 2005, 10:19
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Is X^2+Y^2 > 6?

1. (x+y)^2 > 6
2. xy = 2
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Re: DS [#permalink] New post 19 Nov 2005, 10:31
imaru wrote:
Is X^2+Y^2 > 6?

1. (x+y)^2 > 6
2. xy = 2


1. we have x^2+y^2> [(x+y)^2]/2 >6/2=3 , can't conclude if x^2+y^2>6 ---> insuff

2. we have x^2+y^2>2xy=4 , can't conclude if x^2+y^2> 6 ---> insuff

1 and 2
(x+y)^2= x^2+ y^2 + 2xy>6, xy= 2 ---> x^2+y^2>6-4=2 ---> cant conclude if x^2+y^2> 6 ---> insuff.
Re: DS   [#permalink] 19 Nov 2005, 10:31
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Is X^2+Y^2 > 6? 1. (x+y)^2 > 6 2. xy = 2

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