I am thinking the question is aksing is X^2Y^4 a multiple of 49?
without knowing what Y is we cant really know right?
the question is aksing X^2Y^4=K.49?
statement 1) says x=7K, therefore x^2=49K right!
[(49K)*(y^4)]/49, without knowing what Y is we dont know...
2) same problem...
sorry I meant the answer should be E...I dont know how I said B...it is clearly E!
I will go with D
fresinha12, The question is asking only if there are 2 7s in x^2*y^4 and not about integers.