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# Is x^2 = y^4/(y^4)^(1/2) ?

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Intern
Joined: 17 Jan 2012
Posts: 41
GMAT 1: 610 Q43 V31
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Kudos [?]: 66 [0], given: 16

Is x^2 = y^4/(y^4)^(1/2) ? [#permalink]  28 Jan 2012, 10:53
00:00

Difficulty:

45% (medium)

Question Stats:

78% (01:51) correct 22% (04:19) wrong based on 18 sessions
Is x^2 = y^4/(y^4)^(1/2) ?

(1) -1 < x < 0 < y < 1 < 1-x+y
(2) |x| = |y|
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 28289
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Kudos [?]: 45319 [0], given: 6647

Re: Is X^2 = Y^4/(Y^4)^(1/2)? [#permalink]  28 Jan 2012, 11:22
Expert's post
docabuzar wrote:
Is X^2 = Y^4/(Y^4)^(1/2) ?

A. -1 < x < 0 < y < 1 < 1-x+y

B. IxI = IyI

Is $$x^2=\frac{y^4}{\sqrt{y^4}}$$?

Note that: realistic GMAT question would have mentioned that $$y\neq{0}$$, as it's in denominator.

Is $$x^2=\frac{y^4}{\sqrt{y^4}}$$ --> is $$x^2=\frac{y^4}{y^2}$$? --> is $$x^2=y^2$$? --> is $$|x|=|y|$$?

(1) -1 < x < 0 < y < 1 < 1-x+y. Clearly insufficient: if $$x=-\frac{1}{2}$$ and $$y=\frac{1}{2}$$ then the answer is YES but if $$x=-\frac{1}{3}$$ and $$y=\frac{1}{2}$$ then the answer is NO.

(2) |x|=|y|. Directly gives an YES answer to the question.

_________________
Re: Is X^2 = Y^4/(Y^4)^(1/2)?   [#permalink] 28 Jan 2012, 11:22
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