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Is x^2 = y^4/(y^4)^(1/2) ?

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Is x^2 = y^4/(y^4)^(1/2) ? [#permalink] New post 28 Jan 2012, 10:53
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73% (01:40) correct 27% (04:19) wrong based on 15 sessions
Is x^2 = y^4/(y^4)^(1/2) ?

(1) -1 < x < 0 < y < 1 < 1-x+y
(2) |x| = |y|
[Reveal] Spoiler: OA
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Re: Is X^2 = Y^4/(Y^4)^(1/2)? [#permalink] New post 28 Jan 2012, 11:22
Expert's post
docabuzar wrote:
Is X^2 = Y^4/(Y^4)^(1/2) ?

A. -1 < x < 0 < y < 1 < 1-x+y

B. IxI = IyI


Is x^2=\frac{y^4}{\sqrt{y^4}}?

Note that: realistic GMAT question would have mentioned that y\neq{0}, as it's in denominator.

Is x^2=\frac{y^4}{\sqrt{y^4}} --> is x^2=\frac{y^4}{y^2}? --> is x^2=y^2? --> is |x|=|y|?

(1) -1 < x < 0 < y < 1 < 1-x+y. Clearly insufficient: if x=-\frac{1}{2} and y=\frac{1}{2} then the answer is YES but if x=-\frac{1}{3} and y=\frac{1}{2} then the answer is NO.

(2) |x|=|y|. Directly gives an YES answer to the question.

Answer: B.
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Re: Is X^2 = Y^4/(Y^4)^(1/2)?   [#permalink] 28 Jan 2012, 11:22
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