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Is X>3? 1) (x-3)(x-2)(x-1)>0 2) x>1

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Is X>3? 1) (x-3)(x-2)(x-1)>0 2) x>1 [#permalink] New post 04 Jul 2007, 01:30
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Is X>3?

1) (x-3)(x-2)(x-1)>0
2) x>1

Please explain your answer.
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 [#permalink] New post 04 Jul 2007, 02:03
St1: sufficient. we can work out the legal range of x.
St2: insufficient. x could be 2.

Ans A
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 [#permalink] New post 04 Jul 2007, 02:59
E.

Statement1) 1<x<2 or 3<x> INSUFF.
Statement2) 1<x> INSUFF

Statement 1+2) gives 1<x<2 or 3<x INSUFF. for the same reason as Staement1.
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 [#permalink] New post 04 Jul 2007, 03:13
'E'.

Stmt1: (x-3)(x-2)(x-1)>0 is satisfied for x > 3 and 1<x<2
so INSUFF

Stmt2: INSUFF

Taken them together:

x> 1 and (x-3)(x-2)(x-1)>0

x > 3 and 1<x<2

Hence INSUFF
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 [#permalink] New post 04 Jul 2007, 09:03
yes answer is E . Tricky ones. Always consider fractions and decimals if working with the strategy of plugging numbers.
  [#permalink] 04 Jul 2007, 09:03
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