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Is x a negative number? (1) x2 is a positive number. (2) x [#permalink]
 31 May 2009, 07:23
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Is x a negative number?
(1) x2 is a positive number.
(2) x · |y| is not a positive number.
Please discuss.
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Manager
Joined: 08 Feb 2009
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I think the answer is C, assuming statement 1 refers to x^2
(1) \Rightarrow x = \pm
(2) If x = -ve, then x . |y| = Not Positive \Rightarrow x = -ve
If x = 0, then x. |y| = Not Positive \Rightarrow x = Not -ve.
Combining both the statements,
x = -ve.
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Manager
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Even I marked it as C but the OA is E. REally not sure why.. Manhattan provided OA as E goldeneagle94 wrote: I think the answer is C, assuming statement 1 refers to x^2
(1) \Rightarrow x = \pm
(2) If x = -ve, then x . |y| = Not Positive \Rightarrow x = -ve
If x = 0, then x. |y| = Not Positive \Rightarrow x = Not -ve.
Combining both the statements,
x = -ve.
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Manager
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prinits wrote: Even I marked it as C but the OA is E. REally not sure why.. Manhattan provided OA as E goldeneagle94 wrote: I think the answer is C, assuming statement 1 refers to x^2
(1) \Rightarrow x = \pm
(2) If x = -ve, then x . |y| = Not Positive \Rightarrow x = -ve
If x = 0, then x. |y| = Not Positive \Rightarrow x = Not -ve.
Combining both the statements,
x = -ve. Answer can be E only if we consider the possibility that y = 0.
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Manager
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Stmt 1 - Tells us that X is either -ve or +ve.
Stmt 2 - Tells us that X is either -ve or 0.
By combining the 2 stmt. we can only negate that X is not positive (due to stmt b) however still it can be -ve or 0.
Hence E.
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Manager
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mdfrahim wrote: Stmt 1 - Tells us that X is either -ve or +ve.
Stmt 2 - Tells us that X is either -ve or 0.
By combining the 2 stmt. we can only negate that X is not positive (due to stmt b) however still it can be -ve or 0.
Hence E. Why can't we negate that X is not equal to 0.
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Manager
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Thx. goldeneagle94 for pointing a mistake in my explanation.
I agree with you that option E is possible if we consider that y can be 0.And we had to consider that ?
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Manager
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mdfrahim wrote: Thx. goldeneagle94 for pointing a mistake in my explanation.
I agree with you that option E is possible if we consider that y can be 0.And we had to consider that ? I am not completely sure if we can consider a |y| to be 0.
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Senior Manager
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Why not .??
|Y| when equated to Zero, the value of X varies..
hence IMO the answer shud be E.
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Quote: Why not .??
|Y| when equated to Zero, the value of X varies..
hence IMO the answer shud be E.
can 0 be considered positive number? Quote: Is x a negative number?
(1) x2 is a positive number.
(2) x · |y| is not a positive number.
Stat 1 and 2 As x2 is a positive number and x.|y| is not a positive number - x should be a negative number? I think the answer should be C. correct me if I am wrong..
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Manager
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I have a mistake when ignore y. Yes y can be 0 and from 2) x can be +ve, 0 or -ve
With 1) x can be +ve or -ve
together x can be +ve or -ve, not suf
Hence E
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prinits wrote: Is x a negative number?
(1) x2 is a positive number.
(2) x · |y| is not a positive number.
Please discuss. 1)x^2 positive insuff could be - or+ 2) x-|y| negative x<|y| x could be 4 and |y| could be 5 or x could be -4 and |y|could be 5 insuff together no added info E
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prinits wrote: Is x a negative number?
(1) x2 is a positive number.
(2) x · |y| is not a positive number.
Please discuss. Remember, 0 is neither positive nor negative on the GMAT (but it is even). (1) x^{2} > 0\longrightarrow x<0 OR x>0INSUFFICIENT (2) x|y| \leq 0\longrightarrow y=0 or x \leq 0INSUFFICIENT (1&2) either y=0 & x>0 or x<0Final Answer, E.
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