is x>0?

1. \(x^2=positive.\)

NS. x could be both a positive number and a negative number.

2 x|y| is not a positive number

different scenarios unfold from this expression. x|y|= -ve number, 0, or a positive rational number.

case a) |y| is not zero and x is negative. The answer would be yes

b) if |y| is zero the value of x is concealed (x is either positive or negative).

c) x can be a positive rational number and |y| a positive integer or a positive rational number.

d) x can be a negative rational number and |y| zero.

NS

1+2) combining the informations provided doesn't help to define a clear answer.

NS and the answer is E.

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