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# Is x less than y? (1) x-y+1<0 (2) x-y-1<0

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Manager
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Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]  26 Feb 2011, 15:40
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Is x less than y?

(1) x-y+1<0
(2) x-y-1<0
[Reveal] Spoiler: OA

Last edited by Bunuel on 06 Aug 2012, 23:30, edited 1 time in total.
Edited the question and added the OA.
Math Expert
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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]  26 Feb 2011, 15:47
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Is x less than y?

Is $$x<y$$? --> is $$x-y<0$$?

(1) x-y+1<0 --> $$x-y<-1$$. Sufficient.
(2) x-y-1<0 --> $$x-y<1$$. Not sufficient.

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Senior Manager
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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]  28 Feb 2011, 17:32
yes A it is

1.) x-y<-1 This is satisfied when x<y

2.) x-y<+1 Not sufficient

example x=1.5 and y=1; 1.5-1 < 1
x = - 2 and y= -1; -2 - (-1) < 1

A it is.
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Can someone help on a tricky DS question on Inequalities [#permalink]  06 Aug 2012, 17:52
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.
Manager
Joined: 05 Jul 2012
Posts: 82
Location: India
Concentration: Finance, Strategy
GMAT Date: 09-30-2012
GPA: 3.08
WE: Engineering (Energy and Utilities)
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Re: Can someone help on a tricky DS question on Inequalities [#permalink]  06 Aug 2012, 18:08
gagan_g2k wrote:
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.

That's a very easy trap to fall for, I to fell for it.
Added the two inequalities and got x-y <0 and condluded both are necessary
But if you look at x-y +1 < 0 this means that x+y < -1
which means that X-Y < 0 as -1 < 0 , so we can get the answer from one only.

Now looking at 2) X-Y -1< 0 this means that x-y < 1 which doesn,t clearly mean that x<y as something less than 1 can be positive and negative both.

So A is the answer.
Damn i need more practice !
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Re: Can someone help on a tricky DS question on Inequalities [#permalink]  06 Aug 2012, 21:26
gagan_g2k wrote:
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.

(1) $$x-y+1<0$$ implies $$x-y<-1<0$$, which means $$x-y<0$$ or $$x<y$$.
Hence sufficient.

(2) Take $$x = y = 0$$ for which obviously x is not less than y, but (2) holds. For x = 0 and y = 1, (2) still holds, but now x < y.
Not sufficient.

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Love GMAT Quant questions and running.

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Re: Can someone help on a tricky DS question on Inequalities [#permalink]  06 Aug 2012, 23:35
Expert's post
gagan_g2k wrote:
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.

Merging similar topics. Please refer to the solutions above.

Next, please hide OA under the spoiler!

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Re: Can someone help on a tricky DS question on Inequalities   [#permalink] 06 Aug 2012, 23:35
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# Is x less than y? (1) x-y+1<0 (2) x-y-1<0

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