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# Is x less than y? (1) x-y+1<0 (2) x-y-1<0

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Manager
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Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]

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26 Feb 2011, 16:40
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Is x less than y?

(1) x-y+1<0
(2) x-y-1<0
[Reveal] Spoiler: OA

Last edited by Bunuel on 07 Aug 2012, 00:30, edited 1 time in total.
Edited the question and added the OA.
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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]

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26 Feb 2011, 16:47
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Is x less than y?

Is $$x<y$$? --> is $$x-y<0$$?

(1) x-y+1<0 --> $$x-y<-1$$. Sufficient.
(2) x-y-1<0 --> $$x-y<1$$. Not sufficient.

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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]

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28 Feb 2011, 18:32
yes A it is

1.) x-y<-1 This is satisfied when x<y

2.) x-y<+1 Not sufficient

example x=1.5 and y=1; 1.5-1 < 1
x = - 2 and y= -1; -2 - (-1) < 1

A it is.
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Re: Can someone help on a tricky DS question on Inequalities [#permalink]

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06 Aug 2012, 19:08
gagan_g2k wrote:
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.

That's a very easy trap to fall for, I to fell for it.
Added the two inequalities and got x-y <0 and condluded both are necessary
But if you look at x-y +1 < 0 this means that x+y < -1
which means that X-Y < 0 as -1 < 0 , so we can get the answer from one only.

Now looking at 2) X-Y -1< 0 this means that x-y < 1 which doesn,t clearly mean that x<y as something less than 1 can be positive and negative both.

Damn i need more practice !
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Re: Can someone help on a tricky DS question on Inequalities [#permalink]

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06 Aug 2012, 22:26
gagan_g2k wrote:
Is x less than y?
(1) x-y+1<0
(2) x-y-1<0

The official answer is a but as per my solution it should be d.

(1) $$x-y+1<0$$ implies $$x-y<-1<0$$, which means $$x-y<0$$ or $$x<y$$.
Hence sufficient.

(2) Take $$x = y = 0$$ for which obviously x is not less than y, but (2) holds. For x = 0 and y = 1, (2) still holds, but now x < y.
Not sufficient.

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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]

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21 Aug 2015, 12:31
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15 Jul 2016, 01:23
Is x>y?

Statement 1: x-y-1>0

Statement 2: x-y+1>0
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15 Jul 2016, 01:51
Silviax wrote:
Is x>y?

Statement 1: x-y-1>0

Statement 2: x-y+1>0

Given x>y

Then we need to find x-y > 0 ?

Stat 1: x-y-1>0
=> x-y > 1...Sufficient.

Stat 2: x-y + 1 > 0.
=> x-y > -1... Insufficient ( Since we need to seek x-y > 0 )

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15 Jul 2016, 02:01
The way you explained makes a lot more sense than the official explanation of Magoosh.

I can now see that statement 1 is sufficient by itself.
Thanks!
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15 Jul 2016, 02:10
Perfect solution given....

Sent from my A0001 using GMAT Club Forum mobile app
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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0 [#permalink]

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15 Jul 2016, 02:18
Silviax wrote:
Is x>y?

Statement 1: x-y-1>0

Statement 2: x-y+1>0

Merging similar topics. Please refer to the solutions above.
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Re: Is x less than y? (1) x-y+1<0 (2) x-y-1<0   [#permalink] 15 Jul 2016, 02:18
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