Is x/p(p 2 + q 2 + r 2 ) = x

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Is x/p(p 2 + q 2 + r 2 ) = x [#permalink]

03 Feb 2013, 18:45

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Is \frac{x}{p} (p 2 + q 2 + r 2 ) = xp + yq + zr?

(1) q^2 = r^2

(2) yq = zr

[Reveal] Spoiler: OA

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Re: Is x/p(p 2 + q 2 + r 2 ) = x [#permalink]

03 Feb 2013, 22:46

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carcass wrote:

Is \frac{x}{p} (p 2 + q 2 + r 2 ) = xp + yq + zr?

(1) q^2 = r^2

(2) yq = zr

There are too many variables here so let's focus on logic.

Is \frac{x}{p} (p 2 + q 2 + r 2 ) = xp + yq + zr?
Is xp + \frac{x}{p}(q 2 + r 2 ) = xp + yq + zr?
Is \frac{x}{p}(q 2 + r 2 ) = yq + zr?

(1) q^2 = r^2
Even if q^2 = r^2, there are lots of other variables e.g. x, y and z which can take different values to make the two sides unequal. But if q = r = 0, the two sides become equal so not sufficient alone.

(2) yq = zr
Again, there are no constraints on x and p and they can take different values to make the two sides of the equation unequal. But if q = r = 0, the two sides become equal so not sufficient alone.

Using both together, there are still no constraints on the values x and p can take so the two sides needn't be equal. But if q = r = 0, the two sides become equal so not sufficient.

Answer (E)
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Re: Is x/p(p 2 + q 2 + r 2 ) = x [#permalink]

04 Feb 2013, 04:59

i thought E as well but I wanted to be sure

Thanks

the question was a bit convoluted
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Re: Is x/p(p 2 + q 2 + r 2 ) = x [#permalink]

04 Feb 2013, 14:16

What additional condition must be present for the equation to be true ?

[Reveal] Spoiler:

xq = yp

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Re: Is x/p(p 2 + q 2 + r 2 ) = x [#permalink] 04 Feb 2013, 14:16

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Is x/p(p 2 + q 2 + r 2 ) = x

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