Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is [#permalink]

15 May 2008, 12:04

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Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd

Manager

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Re: DS: consecutive integers [#permalink]

15 May 2008, 12:35

That's what I got....but it's incorrect.

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Re: DS: consecutive integers [#permalink]

15 May 2008, 13:22

giantSwan wrote:

That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

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Re: DS: consecutive integers [#permalink]

15 May 2008, 13:26

rpmodi wrote:

giantSwan wrote:

That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?

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Re: DS: consecutive integers [#permalink]

15 May 2008, 13:29

my bad..A it is..

i dont know why i wrote E

|x-y| just pick number -3 -2, -3+2=-1

3-2=1...

sufficient

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Re: DS: consecutive integers [#permalink]

15 May 2008, 14:23

giantSwan wrote:

Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd

This is a pretty straight forward A.

Just test any consecutive integers. Positive or negative, and even with 0.

2: this is obvs. insuff.

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Re: DS: consecutive integers [#permalink]

15 May 2008, 14:54

giantSwan wrote:

rpmodi wrote:

giantSwan wrote:

That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?

2-1 = 1
1-2 = -1 ; your final answer is +1 or -1 and if you take mod of that answer will always be +1 ; |-1| =1 ; |1|=1 and so A is sufficient

Re: DS: consecutive integers [#permalink] 15 May 2008, 14:54

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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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