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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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Manager
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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is [#permalink] New post 15 May 2008, 11:04
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A
B
C
D
E

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Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 11:35
That's what I got....but it's incorrect.
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 12:22
giantSwan wrote:
That's what I got....but it's incorrect.


I think its A .

take any consecutive integers |x-y| will be 1 , always .
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 12:26
rpmodi wrote:
giantSwan wrote:
That's what I got....but it's incorrect.


I think its A .

take any consecutive integers |x-y| will be 1 , always .



can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 12:29
my bad..A it is..

i dont know why i wrote E :(

|x-y| just pick number -3 -2, -3+2=-1

3-2=1...

sufficient
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 13:23
giantSwan wrote:
Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd


This is a pretty straight forward A.

Just test any consecutive integers. Positive or negative, and even with 0.


2: this is obvs. insuff.
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Re: DS: consecutive integers [#permalink] New post 15 May 2008, 13:54
giantSwan wrote:
rpmodi wrote:
giantSwan wrote:
That's what I got....but it's incorrect.


I think its A .

take any consecutive integers |x-y| will be 1 , always .



can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?


2-1 = 1
1-2 = -1 ; your final answer is +1 or -1 and if you take mod of that answer will always be +1 ; |-1| =1 ; |1|=1 and so A is sufficient
Re: DS: consecutive integers   [#permalink] 15 May 2008, 13:54
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Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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