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Is x/y <1/2? I. x/(x-1) <1/2 II. (x-1)/y <1/2

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Director
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Is x/y <1/2? I. x/(x-1) <1/2 II. (x-1)/y <1/2 [#permalink]

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New post 22 Feb 2006, 01:39
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is x/y <1/2?

I. x/(x-1) <1/2
II. (x-1)/y <1/2
Director
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New post 22 Feb 2006, 02:50
Thus the question asks if x<1/2y

1) this statement gives us x<(x-1)/2, nothing on y insufficient (we only now that x should be negative value)
2) this statement gives us x<1/2y+1, this does not prove anything insufficient

I would choose E
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New post 22 Feb 2006, 03:23
2) plug in x=-2 y=-4, and x=2 y=4

insufficient

1) yields -1<x<0, no information about y

insufficient

1+2) we have a frame for x, and know that (x-1)/y <1/2, so y<-2

I go for C
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New post 22 Feb 2006, 04:21
I would go for E also.

1) x/(x-1) < 1/2
Insufficient to say anything about x/y

2) x/y - 1/y < 1/2
Insufficient to say that x/y < 1/2

1+2) Easiest is to plug numbers.

x=0.5 and y=0.5:
x/(x-1)=-1
(x-1)/y=-1
x/y=1

x=-0.5 and y=0.5
x/(x-1)=1/3
(x-1)/y=-3
x/y=-1

Insufficient.
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New post 22 Feb 2006, 16:57
SimaQ wrote:
Thus the question asks if x<1/2y

1) this statement gives us x<(x-1)/2, nothing on y insufficient (we only now that x should be negative value)
2) this statement gives us x<1/2y+1, this does not prove anything insufficient

I would choose E


how could you conclude this if you do not know if x or y is positive or negative?
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New post 22 Feb 2006, 21:55
Me too for E.
(1) just says that 0 < x < 1 but, does not give any information about Y => Insufficient
(2) tells that x/y < 1/2 + 1/y => THe statement is insufficient.

Both statements taken together are also insufficient because none gives the range of Y.
  [#permalink] 22 Feb 2006, 21:55
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