Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Aug 2016, 05:06

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is x-y+1 greater than x+y-1? 1) x>0 2) y<0

Author Message
TAGS:

### Hide Tags

Manager
Joined: 23 Jan 2011
Posts: 127
Followers: 1

Kudos [?]: 55 [0], given: 13

Is x-y+1 greater than x+y-1? 1) x>0 2) y<0 [#permalink]

### Show Tags

01 Jun 2011, 14:15
00:00

Difficulty:

(N/A)

Question Stats:

63% (01:30) correct 38% (01:41) wrong based on 15 sessions

### HideShow timer Statistics

Is x-y+1 greater than x+y-1?
1) x>0
2) y<0
Manager
Status: Preparing myself to break the sound( 700 )-barrier!
Joined: 15 Feb 2011
Posts: 209
Schools: Texas A&M - Mays; PennState - Smeal; Purdue - Krannert; JohnsHopkins - Carey; Vanderbilt - Owen; WakeForest - Babcock; UBC - Sauder
WE 1: Financial Analyst/Financial Management Trainer - BRAC Afghanistan - 13 months
WE 2: Business Proposal Coordinator - MiDS, Inc. (in Kabul, Afghanistan) - 4 Months (did quit the job bcoz of security concerns)
WE 3: Readers For Readers (A Social Impact Generating Organization) - Co-Founder
Followers: 7

Kudos [?]: 62 [0], given: 136

### Show Tags

01 Jun 2011, 16:58

Because, X and Y can take as many numbers as possible. And there is no specific solution for the two options (x>0 and y<0).

Thanks!
Manager
Joined: 16 Mar 2011
Posts: 189
Followers: 1

Kudos [?]: 6 [0], given: 1

### Show Tags

01 Jun 2011, 18:00
i think that 2 is sufficient only. if y<0 the first expression will be bigger, since x-(-#)+1 will be bigger than x+(-#)-1
Manager
Joined: 23 Jan 2011
Posts: 127
Followers: 1

Kudos [?]: 55 [0], given: 13

### Show Tags

01 Jun 2011, 23:58
Agree with ashkanator. OA is B.

If x= -3, y= -2, then -3-(-2)+1>-3-2-1, this equals 0>-6, Sufficient
If x= 3, y= -2, then 3-(-2)+1>3-2+1, this equals 6>2, sufficient.

B is sufficient.
SVP
Joined: 16 Nov 2010
Posts: 1673
Location: United States (IN)
Concentration: Strategy, Technology
Followers: 34

Kudos [?]: 470 [0], given: 36

### Show Tags

03 Jun 2011, 07:24
Is x - y + 1 > x + y - 1

or, 0 > y - 2

or y < 2

So x is immaterial.

(1) Insufficient

(2)

Sufficient

_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings

Current Student
Joined: 26 May 2005
Posts: 565
Followers: 18

Kudos [?]: 195 [0], given: 13

### Show Tags

03 Jun 2011, 07:31
subhashghosh wrote:
Is x - y + 1 > x + y - 1

or, 0 > y - 2

or y < 2

So x is immaterial.

(1) Insufficient

(2)

Sufficient

How did u get y<2
isnt it y<1?
SVP
Joined: 16 Nov 2010
Posts: 1673
Location: United States (IN)
Concentration: Strategy, Technology
Followers: 34

Kudos [?]: 470 [0], given: 36

### Show Tags

03 Jun 2011, 18:04
Oh yes, you're right, it's a typo, still the answer remains the same, i.e., B.
_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings

Director
Joined: 01 Feb 2011
Posts: 757
Followers: 14

Kudos [?]: 100 [0], given: 42

### Show Tags

03 Jun 2011, 18:12
x-y+1 > x+y-1 ?

y<1 ?

1. Not sufficient

as we dont know anything about y.

2. Sufficient

y<0 => y<1

Manager
Status: Preparing myself to break the sound( 700 )-barrier!
Joined: 15 Feb 2011
Posts: 209
Schools: Texas A&M - Mays; PennState - Smeal; Purdue - Krannert; JohnsHopkins - Carey; Vanderbilt - Owen; WakeForest - Babcock; UBC - Sauder
WE 1: Financial Analyst/Financial Management Trainer - BRAC Afghanistan - 13 months
WE 2: Business Proposal Coordinator - MiDS, Inc. (in Kabul, Afghanistan) - 4 Months (did quit the job bcoz of security concerns)
WE 3: Readers For Readers (A Social Impact Generating Organization) - Co-Founder
Followers: 7

Kudos [?]: 62 [0], given: 136

### Show Tags

04 Jun 2011, 03:55
Schawjibb wrote:

Because, X and Y can take as many numbers as possible. And there is no specific solution for the two options (x>0 and y<0).

Thanks!

Doomed! Miles to go! Now I understand, the answer should be B. Thanks to all!
Manager
Joined: 28 Feb 2011
Posts: 90
Followers: 0

Kudos [?]: 38 [0], given: 2

### Show Tags

04 Jun 2011, 05:05
IMO B..

initially it looked as a smoother and outrightly thought E..but thought, it shouldn't be that easy so dug in a little..nice one
_________________

Fight till you succeed like a gladiator..or doom your life which can be invincible

Manager
Joined: 05 Jul 2010
Posts: 204
Followers: 1

Kudos [?]: 14 [0], given: 18

### Show Tags

04 Jun 2011, 19:21
yes B is the right one. Basically the question is asking is 1-y > y-1, and since Y < 0, 1-y will always be positive where as y-1 will be negative.
Re: DS question   [#permalink] 04 Jun 2011, 19:21
Similar topics Replies Last post
Similar
Topics:
2 Is |x+3| > |2x+y| ? (1) x > 0 (2) y > 0 2 30 Jun 2014, 03:59
16 Is x-y+1 greater than x+y-1 ? 18 30 Sep 2010, 22:11
Is x^2 < x-|y| ? 1) y>x 2) x<0 3 28 Aug 2011, 02:19
3 Is x less than y? (1) x-y+1<0 (2) x-y-1<0 10 26 Feb 2011, 16:40
Is x-y+1 greater than x+y-1 ? (1) x > 0 (2) y < 0 2 18 Aug 2010, 00:30
Display posts from previous: Sort by