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Is x-y+1 greater than x+y-1? 1) x>0 2) y<0

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Is x-y+1 greater than x+y-1? 1) x>0 2) y<0 [#permalink]

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New post 01 Jun 2011, 14:15
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

63% (01:30) correct 38% (01:41) wrong based on 14 sessions

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Is x-y+1 greater than x+y-1?
1) x>0
2) y<0
Manager
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Re: DS question [#permalink]

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New post 01 Jun 2011, 16:58
IMO, the answer is E.

Because, X and Y can take as many numbers as possible. And there is no specific solution for the two options (x>0 and y<0).

Thanks!
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Re: DS question [#permalink]

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New post 01 Jun 2011, 18:00
i think that 2 is sufficient only. if y<0 the first expression will be bigger, since x-(-#)+1 will be bigger than x+(-#)-1
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Re: DS question [#permalink]

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New post 01 Jun 2011, 23:58
Agree with ashkanator. OA is B.

If x= -3, y= -2, then -3-(-2)+1>-3-2-1, this equals 0>-6, Sufficient
If x= 3, y= -2, then 3-(-2)+1>3-2+1, this equals 6>2, sufficient.

B is sufficient.
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Re: DS question [#permalink]

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New post 03 Jun 2011, 07:24
Is x - y + 1 > x + y - 1

or, 0 > y - 2

or y < 2

So x is immaterial.

(1) Insufficient

(2)

Sufficient

Answer - B
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Re: DS question [#permalink]

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New post 03 Jun 2011, 07:31
subhashghosh wrote:
Is x - y + 1 > x + y - 1

or, 0 > y - 2

or y < 2

So x is immaterial.

(1) Insufficient

(2)

Sufficient

Answer - B


How did u get y<2
isnt it y<1?
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Re: DS question [#permalink]

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New post 03 Jun 2011, 18:04
Oh yes, you're right, it's a typo, still the answer remains the same, i.e., B.
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Re: DS question [#permalink]

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New post 03 Jun 2011, 18:12
x-y+1 > x+y-1 ?

y<1 ?

1. Not sufficient

as we dont know anything about y.

2. Sufficient

y<0 => y<1

Answer is B.
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Status: Preparing myself to break the sound( 700 )-barrier!
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Schools: Texas A&M - Mays; PennState - Smeal; Purdue - Krannert; JohnsHopkins - Carey; Vanderbilt - Owen; WakeForest - Babcock; UBC - Sauder
WE 1: Financial Analyst/Financial Management Trainer - BRAC Afghanistan - 13 months
WE 2: Business Proposal Coordinator - MiDS, Inc. (in Kabul, Afghanistan) - 4 Months (did quit the job bcoz of security concerns)
WE 3: Readers For Readers (A Social Impact Generating Organization) - Co-Founder
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Kudos [?]: 61 [0], given: 136

Re: DS question [#permalink]

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New post 04 Jun 2011, 03:55
Schawjibb wrote:
IMO, the answer is E.

Because, X and Y can take as many numbers as possible. And there is no specific solution for the two options (x>0 and y<0).

Thanks!


Doomed! Miles to go! Now I understand, the answer should be B. Thanks to all!
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Re: DS question [#permalink]

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New post 04 Jun 2011, 05:05
IMO B..

initially it looked as a smoother and outrightly thought E..but thought, it shouldn't be that easy so dug in a little..nice one
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Re: DS question [#permalink]

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New post 04 Jun 2011, 19:21
yes B is the right one. Basically the question is asking is 1-y > y-1, and since Y < 0, 1-y will always be positive where as y-1 will be negative.
Re: DS question   [#permalink] 04 Jun 2011, 19:21
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