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Is x > y? (1) x^2 > y^2 (2) x - y > 0

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Is x > y? (1) x^2 > y^2 (2) x - y > 0 [#permalink] New post 14 Jun 2012, 01:07
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Is x > y?

(1) x^2 > y^2
(2) x - y > 0
[Reveal] Spoiler: OA
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Re: Is x > y? [#permalink] New post 14 Jun 2012, 01:11
Is x > y?

(1) x^2 > y^2 --> |x|>|y| --> so, x may or may not be greater than y. Consider: x=-2 and y=1 for a NO answer and x=2 and y=1 for an YES answer. Not sufficient.

(2) x - y > 0 --> x>y. Directly answers the question. Sufficient.

Answer: B.

Hope it's clear.
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Intern
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Re: Is x > y? [#permalink] New post 14 Jun 2012, 01:16
Bunuel wrote:
Is x > y?

(1) x^2 > y^2 --> |x|>|y| --> so, x may or may not be greater than y. Consider: x=-2 and y=1 for a NO answer and x=2 and y=1 for an YES answer. Not sufficient.

(2) x - y > 0 --> x>y. Directly answers the question. Sufficient.

Answer: B.

Hope it's clear.

thanks for the help :)
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Re: Is x > y? (1) x^2 > y^2 (2) x - y > 0 [#permalink] New post 14 Jun 2012, 01:30
sarb wrote:
Is x > y?

(1) x^2 > y^2
(2) x - y > 0

Hi,

x>y?

Using (1),
x^2 > y^2
or x^2 - y^2>0
or (x-y)(x+y)>0
so, either x-y>0 & x+y>0
or x-y<0 & x+y<0
so, x may or may not be less than y. Insufficient.

Using (2),
x-y>0
or x>y, so answer to question is Yes. Sufficient

Thus, answer is (B)

Regards,
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Re: Is x > y? (1) x^2 > y^2 (2) x - y > 0 [#permalink] New post 14 Jun 2012, 01:33
cyberjadugar wrote:
sarb wrote:
Is x > y?

(1) x^2 > y^2
(2) x - y > 0

Hi,

x>y?

Using (1),
x^2 > y^2
or x^2 - y^2>0
or (x-y)(x+y)>0
so, either x-y>0 & x+y>0
or x-y<0 & x+y<0
so, x may or may not be less than y. Insufficient.


Using (2),
x-y>0
or x>y, so answer to question is Yes. Sufficient

Thus, answer is (B)

Regards,


thanks a lot for helping me :)
Re: Is x > y? (1) x^2 > y^2 (2) x - y > 0   [#permalink] 14 Jun 2012, 01:33
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