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# Is |x|>|y|? 1) x^2>y^2 2) x>y

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Senior Manager
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Is |x|>|y|? 1) x^2>y^2 2) x>y [#permalink]  04 Oct 2007, 19:26
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Is |x|>|y|?
1) x^2>y^2
2) x>y
Intern
Joined: 03 Oct 2007
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Re: gmatprep DS [#permalink]  04 Oct 2007, 20:17
r019h wrote:
Is |x|>|y|?
1) x^2>y^2
2) x>y

1) is sufficient
2) is insufficient

Director
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Schools: University of Chicago, Wharton School
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Re: gmatprep DS [#permalink]  04 Oct 2007, 22:12
r019h wrote:
Is |x|>|y|?

1) x^2>y^2
2) x>y

interesting..

1: no matter whether x and y are fraction, -ve or +ve, if x^2 > y^2, then lxl > lyl.
2. not true. if x = -1 and y = -5, it doesnot hold. if x and y +ves, then it holds.

so A.
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Re: gmatprep DS [#permalink]  04 Oct 2007, 22:16
r019h wrote:
Is |x|>|y|?
1) x^2>y^2
2) x>y

A.

Stat 1: If x^2 > y^2 then |x| has to be greater than |y|; suff.

Stat 2: Insuff. Plug in for x and y to prove.
Senior Manager
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yep, OA is A. I tend to get nervous about modulus problems.
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Re: gmatprep DS [#permalink]  06 Oct 2007, 08:14
r019h wrote:
Is |x|>|y|?
1) x^2>y^2
2) x>y

Nice prob. I noticed a while back that essentially |x| is going to give the same result as x^2 in terms of negative/positive.

So S1 is suff.

S2: can be 3>2. So yes.

or can be -2>-3 So no.

So in terms of |x| and x^2, whenever you see something like this can think of the two as interchangable ONLY for determining the number as + or -. Its how I do it, and works fine. May confuse others.

A it is.
Re: gmatprep DS   [#permalink] 06 Oct 2007, 08:14
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