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# Is X>Y? 1). (X-Y)/X>0 2). (X^2-Y^2)/X^2>0 Can

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Intern
Joined: 23 Mar 2007
Posts: 10
Followers: 0

Kudos [?]: 0 [0], given: 0

Is X>Y? 1). (X-Y)/X>0 2). (X^2-Y^2)/X^2>0 Can [#permalink]  01 May 2007, 23:17
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is X>Y?
1). (X-Y)/X>0
2). (X^2-Y^2)/X^2>0

Can someone explain what are the basic rules to solve Qs like the one above. I am always confused.
Thanks.
BTW- OA is E
SVP
Joined: 01 May 2006
Posts: 1798
Followers: 8

Kudos [?]: 102 [0], given: 0

X>Y?

From 1
(X-Y)/X>0

implies that:
o X > 0 then, X-Y > 0 and X > Y
OR
o X < 0 then, X-Y < 0 and X < Y

INSUFF.

From 2
(X^2-Y^2)/(X^2)>0
<=> X^2 > Y^2
<=> |x| > |y|

Implies that:
o If x > 0, then x > y > -x
OR
o If x < 0, then -x > y > x

INSUFF.

Both (1) & (2)
We arrive to the same conclusion with both. So we add nothing nothing new to one another by combining them.
o X > 0 : X > Y
OR
o X < 0 : Y < X

INSUFF.
Intern
Joined: 09 Apr 2007
Posts: 12
Followers: 0

Kudos [?]: 0 [0], given: 0

I would say the easiest way to solve such problems would be to substitute and play

For instance in this problem;

Plug n play....

X=4; Y=3 ---> Satisfies statement
X=-4; Y=3 ----> Still Satisfies statement

Eliminate options A and D from your list (helps if u have to guess at the end )

2. (X^2 - Y^2)/X^2

plug n play again...

X=4; Y=3 ----->Satisfies statement
X=-4;Y=3------>still does satisfy.....

BINGO it has to be E......next question pls
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