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# Is x > y ?

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Manager
Joined: 04 Feb 2011
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Is x > y ? [#permalink]  08 Feb 2011, 10:09
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Difficulty:

25% (medium)

Question Stats:

69% (01:52) correct 31% (00:48) wrong based on 70 sessions
Is x > y ?

(1) (x - y)(x - y) > 0
(2) y > 0
[Reveal] Spoiler: OA

Last edited by Bunuel on 06 Nov 2012, 04:36, edited 1 time in total.
Renamed the topic and edited the question.
Math Expert
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Re: data sufficiency [#permalink]  08 Feb 2011, 10:35
Expert's post
Lolaergasheva wrote:
Is x > y ?
(I) (x - y)(x - y) > 0
(II) y > 0

Is $$x>y$$? --> is $$x-y>0$$?

(1) (x - y)(x - y) > 0 --> $$(x-y)^2>0$$: only says that $$x-y\neq{0}$$ --> $$x\neq{y}$$ (square of a number is always more than or equal to zero. Square of a number equals to zero when the number itself is a zero. Now, as we are given that the square of a number is strictly more than zero thus this number doesn't equal to zero). Not sufficient.

(2) y > 0. Clearly insufficient.

(1)+(2) All we know is that $$x\neq{y}$$ and $$y>0$$ --> insufficient to say whether $$x>y$$. Not sufficient.

Answer: E.
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Manager
Status: Quant 50+?
Joined: 02 Feb 2011
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Concentration: Strategy, Finance
Schools: Tuck '16, Darden '16
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Re: data sufficiency [#permalink]  08 Feb 2011, 16:26
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This post received
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For these types of questions I find it easier to just check extreme solutions

if x = -100, y = 1 both expressions are true
if x = 4, y = 3 both expressions are true

In one example x > y in the other y > x therefore e
Manager
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Re: Is x > y ? (I) (x - y)(x - y) > 0 (II) y > 0 (A) [#permalink]  05 Nov 2012, 04:22
Lolaergasheva wrote:
Is x > y ?
(I) (x - y)(x - y) > 0
(II) y > 0

A)
(X-Y)^2 >0
|X-Y|>0
Cannot comment if X>Y.

B) NS

Together
Y>0 and X>Y or X<Y
Still NS.

E answer
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Re: Is x > y ? [#permalink]  04 Dec 2014, 15:15
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Re: Is x > y ?   [#permalink] 04 Dec 2014, 15:15
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