manimgoindowndown wrote:

Is x > y?

(1) x^2 > y

(2) x – |y| > 0

My understtanding: All statement 1 tells us for sure is x is not 0

Statement 2 we can break into two staments

x>y

OR

x>-y

What I dont get is only one of those statements being true makes B the correct choice...so how is B the correct choice when there are two possibilities for a solution?

Yes u got it right way! but u gotta complete it buddy

ya definitely S1 is not sufficent

But S2 is a trap.

x>y

OR

x>-y

assume numbers for x and y in this case

let x=4 and y=3 so 4>3

like wise x=4 and y=-3 this also 4>-3

So x>|y| always will be x>y

Hope i helped u

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