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# Is x > y?

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Intern
Joined: 04 Jul 2013
Posts: 6
WE: Consulting (Non-Profit and Government)
Followers: 0

Kudos [?]: 11 [0], given: 5

Is x > y? [#permalink]

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22 Aug 2013, 10:38
2
This post was
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Difficulty:

25% (medium)

Question Stats:

69% (01:48) correct 31% (00:46) wrong based on 58 sessions

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Is x > y?

(1) x - 5 > y - 5
(2) x^2> xy

[Reveal] Spoiler:
Sol:
1) X-5>Y-5
X-5>Y-5
X-5-Y+5>0
X-Y>0
X>Y

2) X^2>XY
X^2>XY
X^2-XY>0
X(X-Y)>0
X=0 or X=Y
Answer is A
It is because X^2>XY has two result (1) X=0 (2) X=Y. this is why we ruled out other option like C and D.

I get confused many times.
Please clear this confusion.
[Reveal] Spoiler: OA

Last edited by Bunuel on 22 Aug 2013, 10:44, edited 1 time in total.
Edited the question.
Math Expert
Joined: 02 Sep 2009
Posts: 34449
Followers: 6271

Kudos [?]: 79582 [1] , given: 10022

Re: Is x > y? [#permalink]

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22 Aug 2013, 11:39
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Expert's post
sehgalnikhil wrote:
Hi Bunnel,

Can you explain the 2nd part of the Question - i.e Why we have to consider this part "OR x<0 and x-y<0 --> x<y (answer NO, for example consider x=-1 and y=0). Not sufficient"

Thanks.

Given: x(x-y)>0 --> the product of two multiples (x and x-y) is greater than zero, which means that either both multiples are positive (x>0 and x-y>0) or both multiples are negative (x<0 and x-y<0).

Hope it's clear.
_________________
Math Expert
Joined: 02 Sep 2009
Posts: 34449
Followers: 6271

Kudos [?]: 79582 [0], given: 10022

Re: Is x > y? [#permalink]

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22 Aug 2013, 10:49
Is x > y?

(1) x - 5 > y - 5 --> add 5 to both parts: $$x > y$$. Sufficient.

(2) x^2> xy --> $$x(x-y)>0$$ --> $$x>0$$ and $$x-y>0$$ --> $$x>y$$ (answer YES, for example consider $$x=1$$ and $$y=0$$) OR $$x<0$$ and $$x-y<0$$ --> $$x<y$$ (answer NO, for example consider $$x=-1$$ and $$y=0$$). Not sufficient.

Answer: A.

Hope this helps.
_________________
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Joined: 24 Jul 2013
Posts: 8
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Kudos [?]: 3 [0], given: 0

Re: Is x > y? [#permalink]

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22 Aug 2013, 11:29
Hi Bunnel,

Can you explain the 2nd part of the Question - i.e Why we have to consider this part "OR x<0 and x-y<0 --> x<y (answer NO, for example consider x=-1 and y=0). Not sufficient"

Thanks.
Intern
Joined: 24 Jul 2013
Posts: 8
Followers: 0

Kudos [?]: 3 [0], given: 0

Re: Is x > y? [#permalink]

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22 Aug 2013, 11:45
That what i skip sometimes while doing inequalities - Considering both -ve and +ve - anyways thnaks.
Re: Is x > y?   [#permalink] 22 Aug 2013, 11:45
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# Is x > y?

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