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2) X^2>XY X^2>XY X^2-XY>0 X(X-Y)>0 X=0 or X=Y Answer is A It is because X^2>XY has two result (1) X=0 (2) X=Y. this is why we ruled out other option like C and D.

I get confused many times. Please clear this confusion.

(1) x - 5 > y - 5 --> add 5 to both parts: \(x > y\). Sufficient.

(2) x^2> xy --> \(x(x-y)>0\) --> \(x>0\) and \(x-y>0\) --> \(x>y\) (answer YES, for example consider \(x=1\) and \(y=0\)) OR \(x<0\) and \(x-y<0\) --> \(x<y\) (answer NO, for example consider \(x=-1\) and \(y=0\)). Not sufficient.

Can you explain the 2nd part of the Question - i.e Why we have to consider this part "OR x<0 and x-y<0 --> x<y (answer NO, for example consider x=-1 and y=0). Not sufficient"

Can you explain the 2nd part of the Question - i.e Why we have to consider this part "OR x<0 and x-y<0 --> x<y (answer NO, for example consider x=-1 and y=0). Not sufficient"

Thanks.

Given: x(x-y)>0 --> the product of two multiples (x and x-y) is greater than zero, which means that either both multiples are positive (x>0 and x-y>0) or both multiples are negative (x<0 and x-y<0).

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