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The best solution is to start from statement 2.
This gives us that |x| = |y| and x and y can be positive/negative or both equal to zero. It is not sufficient.

Statement 1 gives us nothing by itself, just some relationship.

However, when we combine the two statements - we see that absolute values of x and y are equal and that x is greater than y, meaning that x is positive and y is negative and neither are equal to zero. Therefore, x > y^2 is true.

I am not sure about this OA/OE , can some Math experts validate/invalidate this OE with a better example.

even if X is greater than Y, is lXl = lYl, y^2 must be greater than X

The question here is "Is x > y^2 ?" we can answer that using 1 and 1 . I agree the last part o the OE looks incorrect " Therefore, x > y^2 is true.
". But the OA still remains C.

we can only know that /y/ = /x/........" THEY MIGHT EVEN BE = ZERO OR 1 " insuff

BOTH

FROM TWO

if this is true then for x>y^2 to be true, they both has to be fractions where x is a positive fraction and y is a negative or positive
equal fraction ...........insuff

FROM ONE

BOTH can never be a fraction IN THE SAME TIME because

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