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Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0

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Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0 [#permalink] New post 02 Sep 2008, 06:41
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38% (02:43) correct 63% (01:44) wrong based on 96 sessions
Is x > y^2?

(1) x > y + 5
(2) x^2 - y^2 = 0

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-y-2-1-x-y-5-2-x-2-y-97142.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 22 Jun 2012, 06:35, edited 1 time in total.
Edited the question and added the OA. Topic is locked.
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Re: DS : m02 #19 [#permalink] New post 02 Sep 2008, 07:08
St 2 : x^2 = y^2 Hence x cannot be > y^2.
St.1: x> y+5. Multiple values can be substituted for x, y.-- Insufficient
Therefore, ans should be B
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Re: DS : m02 #19 [#permalink] New post 02 Sep 2008, 07:23
KASSALMD wrote:
St 2 : x^2 = y^2 Hence x cannot be > y^2.
St.1: x> y+5. Multiple values can be substituted for x, y.-- Insufficient
Therefore, ans should be B


x=1/2 y=1/2 x>y^2 true

x=2 y=2 x>y^2 false

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Re: DS : m02 #19 [#permalink] New post 02 Sep 2008, 10:49
Guys,

Its not B.

For Statement 2:
There are two answers.. Insufficient.
x=1/2 y=1/2 x>y^2 true

x=2 y=2 x>y^2 false

combine

x and y must have opposite sign because x>y+5

x>-x+5
x>2.5

Sufficient

Should be C.

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Re: DS : m02 #19 [#permalink] New post 02 Sep 2008, 11:04
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Real good one! Thanks for the post.
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Re: DS : m02 #19 [#permalink] New post 02 Sep 2008, 13:21
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x2suresh wrote:
Guys,

Its not B.

For Statement 2:
There are two answers.. Insufficient.
x=1/2 y=1/2 x>y^2 true

x=2 y=2 x>y^2 false

combine

x and y must have opposite sign because x>y+5

x>-x+5
x>2.5


Sufficient

Should be C.


thats the trick.
good stuff

OA is C
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Re: Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0 struggling [#permalink] New post 22 Jun 2012, 04:45
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Thnx For the explanation
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Re: Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0 struggling [#permalink] New post 22 Jun 2012, 06:30
seems like answer is C, as it is not mentioned they are integers!

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Re: Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0 [#permalink] New post 22 Jun 2012, 06:35
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Is x>y^2?

(1) x>y+5 --> x-y>5. Clearly insufficient, for example: if x=1 and y=-10 then the answer is NO, but if x=10 and y=1 then the answer is YES. Two different answers, hence not sufficient.

(2) x^2-y^2=0 --> (x-y)(x+y)=0 --> so either x-y=0 or x+y=0. Also insufficient: if x=1 and y=1, then answer is NO, buy if x=\frac{1}{2} and y=\frac{1}{2}, then the answer is YES. Two different answers, hence not sufficient.

(1)+(2) As from (1) x-y>5\neq{0}, then from (2) must be true that x+y=0 --> so x=-y --> substitute x in (1) --> -y-y>5 --> y<-\frac{5}{2}<0, as x=-y, then x>\frac{5}{2}>0, so y^2 (or which is the same x^2) will always be more than x, thus the answer to the question "Is x>y^2" is NO. Sufficient.

To elaborate more as x=-y>0, the only chance for x>y^2 to hold true (or which is the same for x>x^2 to hold true) would be if x is fraction (0<x<1). For example if x=\frac{1}{2} and y=-\frac{1}{2} then x=\frac{1}{2}>y^2=\frac{1}{4}. But the fact that x>\frac{5}{2}>0 rules out this option.

Answer: C.

Hope it's clear.

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-y-2-1-x-y-5-2-x-2-y-97142.html

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Re: Is x > y^2? 1. x > y + 5 2. x^2 - y^2 = 0   [#permalink] 22 Jun 2012, 06:35
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