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Is x > y^2 ? 1) x > y+5 2) x^2 - y^2 = 0

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Manager
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Is x > y^2 ? 1) x > y+5 2) x^2 - y^2 = 0 [#permalink] New post 12 Sep 2008, 04:48
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Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0
SVP
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Joined: 07 Nov 2007
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Location: New York
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Re: inequality DS [#permalink] New post 12 Sep 2008, 21:20
jjhko wrote:
Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0



1)
x=7 y=1

x > y^2 --> 7>1 true

x=-2 y=-10
x>y^2 --> -2>100 false

insuffcient
2)
x=+-y

x=2 y=2
2>4 false
x=1/2 y=1/2
1/2>1/4 true

insufficient

combined.
x > y+5
and x=+-y
so x=-y y is negative and x is positive.
when x=2 y=-2
2>4 false
when x=1/2 y=-1/2
1/2>1/4 true
insufficient


E
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Director
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Re: inequality DS [#permalink] New post 12 Sep 2008, 23:16
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jjhko wrote:
Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0



C

from statement 2:

|x| = |y|

from statement 1:
x > y+5

together, x must be positive and y must be negative, and y must be less than -2.5, so absolute value of y must be greater than 2.5, therefore x must be less than y^2
Re: inequality DS   [#permalink] 12 Sep 2008, 23:16
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Is x > y^2 ? 1) x > y+5 2) x^2 - y^2 = 0

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