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# Is x > y ?

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Current Student
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Is x > y ? [#permalink]  02 Dec 2005, 05:37
00:00

Difficulty:

75% (hard)

Question Stats:

35% (02:15) correct 65% (01:17) wrong based on 109 sessions
Is x > y?

(1) 9x = 4y
(2) x = -y
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Apr 2014, 00:53, edited 1 time in total.
Renamed the topic, edited the question and the OA.
Director
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Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.

Last edited by remgeo on 02 Dec 2005, 06:09, edited 1 time in total.
SVP
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Re: DS Inequalities [#permalink]  02 Dec 2005, 06:07
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y

1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
---->insuff
Director
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Re: DS Inequalities [#permalink]  02 Dec 2005, 06:26
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y

1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
---->insuff

Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y
SVP
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Re: DS Inequalities [#permalink]  02 Dec 2005, 06:39
remgeo wrote:
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y

1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
---->insuff

Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y

well, i was too careless, feel extremely frustrated toward sth so didn't have a fresh mind
Manager
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remgeo wrote:
Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.

I don't understand why x and y have to be positive? (frankly I don't totally understand how to 'investigate' #2 either, but I kinda see where you're going with your explanation there...)
Director
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Location: London
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remgeo wrote:
Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.

I don't understand why x and y have to be positive? (frankly I don't totally understand how to 'investigate' #2 either, but I kinda see where you're going with your explanation there...)

From 1 and 2 we know that x = 4y/9 and x>-y

if y is negative, ie. y = -1, x should be -4/9. But that doesnt satisfy eq 2 which says that x should be greater than -y as -4/9 is not greater than -(-1)
So y has to be positive, ie. y = 1, x = 4/9, and x is always > -y
Director
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Posts: 660
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Re: DS Inequalities [#permalink]  02 Dec 2005, 07:03
laxieqv wrote:
remgeo wrote:
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y

1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
---->insuff

Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y

well, i was too careless, feel extremely frustrated toward sth so didn't have a fresh mind

You have suddenly become violent now. From the nice school kids you have turned out to be this fierce woman. Is this your new way to attack GMAT?
SVP
Joined: 24 Sep 2005
Posts: 1891
Followers: 11

Kudos [?]: 142 [0], given: 0

Re: DS Inequalities [#permalink]  02 Dec 2005, 09:20
remgeo wrote:
You have suddenly become violent now. From the nice school kids you have turned out to be this fierce woman. Is this your new way to attack GMAT?

well, I just burst out due to some bad thing which happened to me here ( "here" doesn't mean this forum ) ...need time to calm down *sigh*
Current Student
Joined: 28 Dec 2004
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Location: New York City
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OK I get C...whats the OA?

Is x>y?

1. 9x=4y
2. x>-y

(1) Insuff...x=o, y=o then x=y or x=1/9 and y=1/4 then Y> X...

(2) insuff...we dont know the realationship between x and +y....

together yes...we know that x and Y are not equal to 0....sufficient
Intern
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Re: Inequality Challenge [#permalink]  31 Oct 2009, 14:01
(1) 9x=4y
4/9y<y, while y>0, and
4/9y>y, while y<0. While we cannot determine sign of x or y, (1) alone is NOT SUFFICIENT.

(2) x=-y
x>y for all x>0, and
x<y for all x<0. But again sign of x or y is not known. So, (2) alone is NOT SUFFICIENT.

Both statements together could be true only if x=y=0.

KUDOS if you find it helpful
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KUDOS if you find it helpful

Manager
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Re: Inequality Challenge [#permalink]  31 Oct 2009, 14:04
1
KUDOS
Statement 1: 9x = 4y

x = (4/9)y

Therefore,

If y < 0: x > y
If y > 0: x < y
If y = 0: x = y

Insufficient.

Statement 2: x = -y

If y < 0: x > y
If y > 0: x < y
If y = 0: x = y

Insufficient.

Both Statements Together

(1) 9x = 4y
(2) x = -y

It should be apparent that this is only true iff x = y = 0. Therefore, sufficient!

Senior Manager
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Re: Is x > y? 1. 9x = 4y 2. x = -y [#permalink]  16 Jan 2013, 23:29
slingfox wrote:
Is x > y?

1. 9x = 4y
2. x = -y

Thank you for this question. here is my solution.

1. $$9x=4y$$ also means:
(a) $$\frac{x}{y}=\frac{4}{9}$$ which means y > x NO!
(b) $$\frac{x}{y}=\frac{{-4}}{{-9}}$$ which means x > y YES!
INSUFFICIENT!

2. $$\frac{x}{y}=-1$$ this means:
(a) they have the same number but of different sign, one is negative the other is positive BUT we don't know which one is positive or negative
(b) x = y = 0
INSUFFICIENT!

Combine both:
$$9(-y) = 4y$$
$$13y = 0$$
$$y=0$$ and $$x=0$$

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Impossible is nothing to God.

e-GMAT Representative
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Re: Is x > y? 1. 9x = 4y 2. x = -y [#permalink]  17 Jan 2013, 00:35
Expert's post
slingfox wrote:
Is x > y?

1. 9x = 4y
2. x = -y

Another simpler approach could be...

Statement 1-

Say x= 4, & y=9 => x<y => NO.
But if x= -4, & y=-9 => x>y => Yes.

Insufficient

Statement 2-

Say x= 1, & y=-1 => x>y => Yes.
But if x= -1, & y=1 => x<y => No.

Insufficient

Statement 1, & 2 together-

Only one case is possible => x=y=0. Answer C.

-Shalabh Jain
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Intern
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Re: Is x>y? 1. 9x=4y 2. x>-y [#permalink]  13 Apr 2014, 11:12
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y

in 1 we can reformulate and get x/y= 4/9 this give us 2 case
x>0, y>0 in this case x<Y so answer is no
x<0, y<0 in this case x>y so answer is yes
insuf.....

in 2. we have x>-y this equivalent to x+y>0
so x>y or y>x works here
insuff

both statement together
we can eliminate the second case were x and y are negative then we will be left with x>0 and y>0 which give us the answer no.

Re: Is x>y? 1. 9x=4y 2. x>-y   [#permalink] 13 Apr 2014, 11:12
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