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Is x > y ?

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Is x > y ? [#permalink] New post 02 Dec 2005, 05:37
00:00
A
B
C
D
E

Difficulty:

  85% (hard)

Question Stats:

25% (02:06) correct 75% (01:18) wrong based on 62 sessions
Is x > y?

(1) 9x = 4y
(2) x = -y
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Apr 2014, 00:53, edited 1 time in total.
Renamed the topic, edited the question and the OA.
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 [#permalink] New post 02 Dec 2005, 05:54
Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.

Last edited by remgeo on 02 Dec 2005, 06:09, edited 1 time in total.
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Re: DS Inequalities [#permalink] New post 02 Dec 2005, 06:07
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y


1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
3>-2 and 3>2, answer YES
---->insuff
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Re: DS Inequalities [#permalink] New post 02 Dec 2005, 06:26
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y


1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
3>-2 and 3>2, answer YES
---->insuff


Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y
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Re: DS Inequalities [#permalink] New post 02 Dec 2005, 06:39
remgeo wrote:
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y


1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
3>-2 and 3>2, answer YES
---->insuff


Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y


well, i was too careless, feel extremely frustrated toward sth so didn't have a fresh mind :(
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 [#permalink] New post 02 Dec 2005, 06:56
remgeo wrote:
Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.


I don't understand why x and y have to be positive? (frankly I don't totally understand how to 'investigate' #2 either, but I kinda see where you're going with your explanation there...)
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 [#permalink] New post 02 Dec 2005, 07:00
stretchad wrote:
remgeo wrote:
Edited : It should be C

1) x=4y/9

y=1 x=4/9 ie. x<y
y=-1, x=-4/9 ie. x>y
So insuff

2) x>-y

y=1, x can be 0, 1, 2 etc
ie. can be greater or less than y
y=-1, x can be 2,3,4 etc

insuff

Taking 1) and 2) together
x and y has to be positive.


I don't understand why x and y have to be positive? (frankly I don't totally understand how to 'investigate' #2 either, but I kinda see where you're going with your explanation there...)


From 1 and 2 we know that x = 4y/9 and x>-y

if y is negative, ie. y = -1, x should be -4/9. But that doesnt satisfy eq 2 which says that x should be greater than -y as -4/9 is not greater than -(-1)
So y has to be positive, ie. y = 1, x = 4/9, and x is always > -y
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Re: DS Inequalities [#permalink] New post 02 Dec 2005, 07:03
laxieqv wrote:
remgeo wrote:
laxieqv wrote:
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y


1.x=4/9 y ----> x<= y (the "=" case is when x=y=0) ----> answer to the question : NO
-->suff

3>-4 , but 3<4, answer NO
3>-2 and 3>2, answer YES
---->insuff


Not necessariliy,
If y = -1,
x = -4/9
In that case, x > y


well, i was too careless, feel extremely frustrated toward sth so didn't have a fresh mind :(


You have suddenly become violent now. From the nice school kids you have turned out to be this fierce woman. Is this your new way to attack GMAT? :-D
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Re: DS Inequalities [#permalink] New post 02 Dec 2005, 09:20
remgeo wrote:
You have suddenly become violent now. From the nice school kids you have turned out to be this fierce woman. Is this your new way to attack GMAT? :-D


well, I just burst out due to some bad thing which happened to me here ( "here" doesn't mean this forum :P) ...need time to calm down *sigh*
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 [#permalink] New post 02 Dec 2005, 09:25
OK I get C...whats the OA?

Is x>y?

1. 9x=4y
2. x>-y

(1) Insuff...x=o, y=o then x=y or x=1/9 and y=1/4 then Y> X...

(2) insuff...we dont know the realationship between x and +y....

together yes...we know that x and Y are not equal to 0....sufficient
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Re: Inequality Challenge [#permalink] New post 31 Oct 2009, 14:01
(1) 9x=4y
Restating statement, we receive x=4/9y,
4/9y<y, while y>0, and
4/9y>y, while y<0. While we cannot determine sign of x or y, (1) alone is NOT SUFFICIENT.

(2) x=-y
x>y for all x>0, and
x<y for all x<0. But again sign of x or y is not known. So, (2) alone is NOT SUFFICIENT.

Both statements together could be true only if x=y=0.

Answer should be C.

KUDOS if you find it helpful ;)
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Re: Inequality Challenge [#permalink] New post 31 Oct 2009, 14:04
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Statement 1: 9x = 4y

x = (4/9)y

Therefore,

If y < 0: x > y
If y > 0: x < y
If y = 0: x = y

Insufficient.

Statement 2: x = -y

If y < 0: x > y
If y > 0: x < y
If y = 0: x = y

Insufficient.

Both Statements Together

(1) 9x = 4y
(2) x = -y

It should be apparent that this is only true iff x = y = 0. Therefore, sufficient!

The answer is C.
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Re: Is x > y? 1. 9x = 4y 2. x = -y [#permalink] New post 16 Jan 2013, 23:29
slingfox wrote:
Is x > y?

1. 9x = 4y
2. x = -y


Thank you for this question. here is my solution.

1. 9x=4y also means:
(a) \frac{x}{y}=\frac{4}{9} which means y > x NO!
(b) \frac{x}{y}=\frac{{-4}}{{-9}} which means x > y YES!
INSUFFICIENT!

2. \frac{x}{y}=-1 this means:
(a) they have the same number but of different sign, one is negative the other is positive BUT we don't know which one is positive or negative
(b) x = y = 0
INSUFFICIENT!

Combine both:
9(-y) = 4y
13y = 0
y=0 and x=0

Answer: C
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Re: Is x > y? 1. 9x = 4y 2. x = -y [#permalink] New post 17 Jan 2013, 00:35
Expert's post
slingfox wrote:
Is x > y?

1. 9x = 4y
2. x = -y

Another simpler approach could be...

Statement 1-

Say x= 4, & y=9 => x<y => NO.
But if x= -4, & y=-9 => x>y => Yes.

Insufficient

Statement 2-

Say x= 1, & y=-1 => x>y => Yes.
But if x= -1, & y=1 => x<y => No.

Insufficient

Statement 1, & 2 together-

Only one case is possible => x=y=0. Answer C.

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Re: Is x>y? 1. 9x=4y 2. x>-y [#permalink] New post 13 Apr 2014, 11:12
GMATT73 wrote:
Is x>y?

1. 9x=4y
2. x>-y


in 1 we can reformulate and get x/y= 4/9 this give us 2 case
x>0, y>0 in this case x<Y so answer is no
x<0, y<0 in this case x>y so answer is yes
insuf.....

in 2. we have x>-y this equivalent to x+y>0
so x>y or y>x works here
insuff

both statement together
we can eliminate the second case were x and y are negative then we will be left with x>0 and y>0 which give us the answer no.

so C is the answer
Re: Is x>y? 1. 9x=4y 2. x>-y   [#permalink] 13 Apr 2014, 11:12
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