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# is x>y?

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Manager
Joined: 31 Mar 2006
Posts: 163
Followers: 1

Kudos [?]: 11 [0], given: 0

is x>y? [#permalink]  29 May 2006, 01:58
Is x>y?
1.(x-y)(x-y)>0
2.y<0

Senior Manager
Joined: 19 Feb 2005
Posts: 487
Location: Milan Italy
Followers: 1

Kudos [?]: 11 [0], given: 0

I'm sorry I misread st 1, so the explanation is not good, I still think the answer is E
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Please allow me to introduce myself: I'm a man of wealth and taste

Last edited by thearch on 29 May 2006, 04:12, edited 1 time in total.
VP
Joined: 07 Nov 2005
Posts: 1132
Location: India
Followers: 3

Kudos [?]: 29 [0], given: 1

Also got E.
Same reasoning as above.
Senior Manager
Joined: 19 Feb 2005
Posts: 487
Location: Milan Italy
Followers: 1

Kudos [?]: 11 [0], given: 0

amansingla4 wrote:

St 1 doesn't help much
whatever square is positive

St 2 by itself is clearly insufficient

Combining doesn't yield any valuable additional piece of information

Right?
_________________

Please allow me to introduce myself: I'm a man of wealth and taste

Director
Joined: 10 Oct 2005
Posts: 531
Location: US
Followers: 1

Kudos [?]: 13 [0], given: 0

Yeah it is E....no doubt
Manager
Joined: 24 Oct 2005
Posts: 169
Followers: 28

Kudos [?]: 121 [0], given: 0

I don't want to spoil the "E" party but I think is "A" (unless I am falling in a trap).

(x-y) (x-y) > 0 is equal to x>y.

so it should be sufficient.
VP
Joined: 29 Dec 2005
Posts: 1349
Followers: 7

Kudos [?]: 30 [0], given: 0

positive soul wrote:
I don't want to spoil the "E" party but I think is "A" (unless I am falling in a trap).

(x-y) (x-y) > 0 is equal to x>y.

so it should be sufficient.

amansingla4 wrote:
Is x>y?
1.(x-y)(x-y)>0
2.y<0

do this way:

st 1. (x-y)(x-y)>0
(x-y)^2 >0. now put some values for x and y, you find either is > than the other.

st 2. y<0 doesnot go anywhere.
Manager
Joined: 24 Oct 2005
Posts: 169
Followers: 28

Kudos [?]: 121 [0], given: 0

Thanks Prof.
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