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Could someone please clarify - When the 2 statements are taken together - i.e x=y^2 and x=2y, we get y^2 = 2y y^2 - 2y=0 y(y-2)=0
Therefore y=0 or y=2 Clearly it creates 2 different answers for the the inequality. I believe (E) should be the answer
On solving this, you do get two different values for y. But variables cannot take values which make an expression undefined e.g. given y/x, x cannot be 0 since division by 0 is not allowed. Given x^y, both x and y cannot be 0 since 0^0 is not defined. Hence y will not take the value 0. y must be 2 only. _________________
Re: Is x^y less than or equal to y^x? [#permalink]
21 Jan 2016, 05:05
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