Is (x-y)/ (x+y) < 1 1) x > 0 2) y < 0

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Is (x-y)/ (x+y) < 1 1) x > 0 2) y < 0 [#permalink]

24 Sep 2009, 18:16

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Is (x-y)/ (x+y) < 1
1) x > 0
2) y < 0
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Re: (x-y)/ (x+y) < 1 [#permalink]

24 Sep 2009, 20:51

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I think it is B.

x-y < x+y => y>0

So stmt 2 gives the answer
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Re: (x-y)/ (x+y) < 1 [#permalink]

24 Sep 2009, 23:26

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seems like an E to me

Stament 1 does not allow for 1 answer:

X = 5, Y may be positive, say 2, then 5-2 / 5+2 < 1, while if Y= -2, then 5-(-2) /5-2 > 1

Same for statement 2.

Both combined allow division by 0: X=1, Y=-1, then 1-(-1) /1-1, which also does not give a clear answer.

even if you take X=2, Y=-1, then get 2-(-1) / 2-1 > 1, while if X=1, Y=-3, then 1-(-3) / 1-3 < 1

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Re: (x-y)/ (x+y) < 1 [#permalink]

25 Sep 2009, 07:53

(x-y)/ (x+y) < 1 reduces to y>0? so my ans = B

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Re: (x-y)/ (x+y) < 1 [#permalink]

25 Sep 2009, 13:51

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1) insuff.
4 cases.
a)y>0 and y<x answer is yes
b)y>0 and y>x answer is yes
c)y<0 and absolute value y>x answer is yes
d)y<0 and absolute value y<x answer is no
2)insuff
4 cases
a and b is like the above where is x>0 and answer is yes
c)x<0 and y<x answer is yes
d)x<0 and y>x answer is no

together
x>0 and y<0
insuff
depends on the comparison between the absolute value of y and x.

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Re: (x-y)/ (x+y) < 1 [#permalink]

27 Sep 2009, 04:00

I would go for E unless statement 2 states Y is < -1, pls post OA

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Re: (x-y)/ (x+y) < 1 [#permalink]

27 Sep 2009, 09:39

(x-y)/(x+y)=(x+y-2y)/(x+y)=1-2y/(x+y) <1 ?

1, x>0, can't find the sign for y/(x+y), insuff
2, y<0, -2y>0 but we don't know whether x+y post or neg insuff

both 1&2, x>0 & y<0 but we don't know x+y>0 or not, insuff

E for me

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Re: (x-y)/ (x+y) < 1 [#permalink]

02 Oct 2009, 04:58

Sometimes its better to put values and check :-D

X=2,
Y=-3

This will the condition true

However,

X=3,
Y=-2

This will make it false.

E :-D

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Re: (x-y)/ (x+y) < 1 [#permalink]

23 Oct 2009, 16:30

Putting numbers is actually a cool strategy.......but it is time consuming....any shortcut way to solve this problem?

Re: (x-y)/ (x+y) < 1 [#permalink] 23 Oct 2009, 16:30

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Is (x-y)/ (x+y) < 1 1) x > 0 2) y < 0

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