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# IS |X-Y| > |x| -|y| 1) y<x 2)xy<0

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IS |X-Y| > |x| -|y| 1) y<x 2)xy<0 [#permalink]

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29 Sep 2007, 23:07
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IS |X-Y| > |x| -|y|

1) y<x
2)xy<0
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Joined: 09 Jul 2007
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Re: DS-ineq [#permalink]

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30 Sep 2007, 00:58
tlntd42 wrote:
IS |X-Y| > |x| -|y|

1) y<x
2)xy<0

http://www.gmatclub.com/forum/t52479
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Joined: 28 Sep 2007
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IS |X-Y| > |x| -|y| [#permalink]

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30 Sep 2007, 05:53
Lets consider 1) y < x.
if x is 3, y could be 2 or less.
|x-y| IS |3-2| = 1
|X| - |y| = 1 . so the equation is not true .
However if y is negative eg -1. |X-Y| |3 - (-1)) = |4| = 4
|X| - |Y| = 3 - 1 = 2. the equation is true.
So A is not sufficient to answer the question.

Lets try B alone. xy <0.
here if x is < 0 y is +ve. if y is less than 0, X is +ve. both cannot be less than 0.
case: x <0
eg : x= -1; y = 1
|X-Y| = |-2| = 2; |X| - |y| = 1 -1 = 0 so the equation is true
eg x = -5 ; y = 10
|X-Y| = |-15| =15; |X| - |y| = -5 so the equation is true.

case y < 0
eg: x = 1; y = -1
|X-Y| = |2| = 2; |X| - |y| = 1 - 1 = 0; so equation is true
eg x = 5 ; y = -10
|X-Y| = |15| = 15; |X| - |y| = 5 - 10 = -5; so equation is true

so in both cases B satisifies the equations.

Answer: B alone is sifficient
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Re: DS-ineq [#permalink]

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30 Sep 2007, 07:44
tlntd42 wrote:
IS |X-Y| > |x| -|y|

1) y<x
2)xy<0

Should be B. if xy<o, then x and y have different signs, which is suff.

1 is not suff cux x and y could have same signs.
Re: DS-ineq   [#permalink] 30 Sep 2007, 07:44
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# IS |X-Y| > |x| -|y| 1) y<x 2)xy<0

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