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Re: Is |x - y|>|x - z|? [#permalink]
25 Aug 2010, 07:14

1

This post received KUDOS

In general for these types of questions, if I'm testing values, are the variables different from each other.. eg should I consider the case where x = y, or x = z unless otherwise stated?

Re: Is |x - y|>|x - z|? [#permalink]
25 Aug 2010, 07:28

Expert's post

krazo wrote:

In general for these types of questions, if I'm testing values, are the variables different from each other.. eg should I consider the case where x = y, or x = z unless otherwise stated?

Sorry if this is a dumb question.. lol

Unless otherwise specified, variables could represent the same number. _________________

I think we need to develop intuition for these kind of questions... from looking at question i was not able to say the answer but after looking at choices, i started to feel it must be E. After less then a minute of thinking i was sure it has to be E.

It is E. We can make out pretty quickly that these are heavily based on values of X, Y, and Z. So it has to be C or E. You are subtracting Y and Z from a fixed value of X. Having absolute values is not going to help. Nice post but! Thanks.

Re: Is |x - y|>|x - z|? (1) |y|>|z| (2) x < 0 [#permalink]
22 May 2012, 17:06

try assuming values y=3 z=2 ... x can be any no. +ve / -ve (take both cases to decide between A & C) but eventualy both did not give answer so E is correct

Re: Is |x - y|>|x - z|? (1) |y|>|z| (2) x < 0 [#permalink]
22 May 2012, 19:20

1

This post received KUDOS

I used the approach below :

1) |y|>|z| will give 4 different cases , I assumed only two y=5 , z=2 & y=-5 , z= -2 No information about x , so x can be =+ ve or -ve , let x = 7 x-y=7-5 =2& x-z= 7-2=5

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