Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

First, remember what do we use the absolute value for ? We use it to express the distance between two real numbers on the number line. So, |x - y| means the distance between x and y, and |x| = |x - 0| means the distance between x and 0. Also, |x + 3| = |x - (-3)| expresses the distance between x and -3. Obviously, |x - y| = |y - x| (it is the same distance).

So, the question can be rephrased as "is the distance between x and y greater that the distance between x and z ?" or "is x closer to z than to y?"

(1) |y| > |z| means that the distance from y to 0 is greater than the distance from z to 0. This in fact is not important in this case. But certainly y and z are distinct. Regardless of wheather y > z or y < z (both cases are possible, try to draw the number line and visualize the points), we can place x closer to either y or z. So, (1) is not sufficient.

(2) Is evidently not sufficient. Take a point x on the number line at the left of 0, then you can place y and z as you please, each one can be closer or farther from x. Also, now you can consider y = z, in which case the two distances are equal.

Evidently, considering (1) and (2) together won't help either. For example, put x at the left of 0, y and z on either side of x such that y < x and z > x, both negative. You can play with each distance and put either y or z closer to x.

Therefore, answer, E. _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Friends, Am new here. Just started to prepare. Please let me know if my thought process on this problem is right.

|X-Y| > |X-Z|?

1) |Y| > |Z|. --- > |Y| = +Y OR -Y --- > |Z| = +Z OR -Z Basis the above, |X-Y| = X-Y OR X+Y OR Y-X OR -Y-X |X-Z| = X-Z OR X+Z OR Z-X OR -Z-X Hence we are not sure which one out of the above matches to give a certain answer.

2) X<0 This by itself is not sufficient because we dont know the signs of Y and Z

1 + 2 , we know X is negative and if we consider the negative value of X in |X-Y| = X-Y OR X+Y OR Y-X OR -Y-X & |X-Z| = X-Z OR X+Z OR Z-X OR -Z-X , still we are unclear which one will certainly answer the question. Hence E.

My approach is to use the distance perspective... |x-z| represents the distance bet. x and z |x-y| represents the distance bet. x and y

1. |y| > |z|

<-----------------------0-------z------y-------> or <--------------y--------0------z-------------> or <--------------y-----z---0---------------------> or <--------------------z----0------------y------->

1. |z| > |y| \(z^2>y^2\) \(z^2-y^2>0=y^2-z^2<0=(y-z)(y+z)<0\) So one between (y-z) (y+z) is negative, the other is positive, but we cannot tell which one is +ve or -ve. \(2x(y-z)>(y+z)(y-z)\) the second part is -ve ((y-z)(y+z)<0) we cannot say anything about 2x(y-z) Not sufficient

2. 0 > x x<0 so the first term is -ve (2x) but we cannot say anything about the other part (...(y-z)>(y+z)(y-z))

(1)+(2) Still not sufficient, let me explain. Here are the combinations ( remeber that one between (y-z) (y+z) is negative and the other positive) \(2x(y-z)>(y+z)(y-z)\) Case one (y-z)-ve: 2x<0 (y-z)<0 (y+z)>0 -veNumber*-veNumber>+veNumber*-veNumber +ve>-ve always true. Case two (y+z)-ve: 2x<0 (y-z)>0 (y+z)<0 -veNumber*+veNumber>-veNumber*+veNumber -veNumber>-veNumber we cannot say if this is true, since we have no numerical value

E

Do I deserve a Kudos for this? _________________

It is beyond a doubt that all our knowledge that begins with experience.

Absolute Value of a number describe the distance of a number from 0 in a number line irrespective of a positive or negative number. Similarly |x-y| gives the distance between two numbers irrespective of their sign. Pick some numbers and you can reach this conclusion.

1)|y| > |z| -> just tells you y is further from z on the number line. It doesn't tell you where x is -> INSUFFICIENT.

2) x < 0. Again doesn't help because we are talking about distance between numbers. We don't any relation between x and y, hence INSUFFICIENT.

Combining 1 and 2 also doesn't give much information. We just know y is farther from z and x is negative. This can be interpreted in multiple ways.

+1 Bunuel.....Nice explanation..I went to the extent of taking examples for each case and solving it..This graphical approach is awesome!!!! _________________

"Kudos" will help me a lot!!!!!!Please donate some!!!

Completed Official Quant Review OG - Quant

In Progress Official Verbal Review OG 13th ed MGMAT IR AWA Structure

Yet to do 100 700+ SC questions MR Verbal MR Quant

Is (x-y)^2 > (x-z)^2 Is (x-y)*(x-y) > (x-z)*(x-z) Is x^2 -2xy + y^2 > x^2 - 2xz + z^2 Is 2xz - 2xy > z^2 - y^2? Is 2(xz-xy) > z^2 - y^2? Is 2x(z-y) > (z+y)*(z-y)?

1. |z| > |y| We can square both sides to factor out in an attempt to understand more about x and y [as we see in the stem - (z+y)*(z-y)]

z^2 - y^2 > 0 (z + y)*(z - y) > 0

So, (z+y)*(z-y) may be both positive or both negative for the product to be greater than zero. However, this tells us nothing about the left hand side. INSUFFICIENT

2. 0 > x

This tells us the the left hand side of 2x(z-y) > (z+y)*(z-y) is positive, however, it tells us nothing about the right hand side. INSUFFICIENT

1+2) We know that the RHS of 2x(z-y) > (z+y)*(z-y) is positive and we also know that 2x is positive as well. However, there is one problem. We have established that (z + y)*(z - y) is positive which means BOTH (z + y)*(z - y) are positive or BOTH (z + y)*(z - y) are negative. We don't know if they are positive or negative though, which means that 2x(z-y) could be positive or negative. This problem could also be tested by picking numbers. INSUFFICIENT

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and equations ensures a solution.

Is |x - y| > |x - z|?

(1) |y| > |z| (2) x < 0

In the original condition there are 3 variables (x,y,z) and since we need to match the number of variables and equations, we need 3 equations. Since there is 1 each in 1) and 2), we need 1 more equation and thus E isl likely the answer and it turns out that E actually is the answer.

In a number line, absolute number depicts the distance between two points. Looking back at the question, Is |x - y| > |x - z|?

(1) |y-0| > |z-0| (2) x < 0

asks if the distance from y to 0 is greater than the distance from z to 0. Essentially is asks if, assuming x is negative, the distance from x to y is greater then the distance from x to z. if x=-1, y=5, z=-2, then the answer is yes, but if y=-5, z=2, x=-4 then the answer is no and therefore it is not sufficient. Therefore the answer is E. However, keep in mind that these direct substitutions are not the key methods but comparing the number of variables and equations in the original condition are. _________________

http://blog.ryandumlao.com/wp-content/uploads/2016/05/IMG_20130807_232118.jpg The GMAT is the biggest point of worry for most aspiring applicants, and with good reason. It’s another standardized test when most of us...

With the limited financing options available to NZ citizens (especially those comme moi who aren't planning to return to work in NZ), I've really had to...

Strategy, innovation, marketing, finance... The second module has been pretty engaging. Though, no lack of memorable times. There is no lack of high profile guest speakers. One of the...