tarek99 wrote:

Is x + y > xy?

(1) x > 0 > y

(2) |y| = x

I know that this can be simple when we experiment with numbers. However, I want to avoid experimenting because I can tell that there is a subtle message in the inequality Is x + y > xy. Would anyone please show how we could abstractly interpret it without doing much math? I know that it's possible, but I just couldn't figure it out in this question.

Thanks

1)x>0>y => x+y>xy say x=1,y=-2 => x+y=-1 > -2

x+y<xy say x=0.5 y=-2 => x+y=-1.5 < -1

INSUFFI

2) |y|=x => x is +ve and and x=value of y where y is +ve or -ve

say y=2 x+y =xy y=x=3 => x+y<xy => INSUFFI

1) and 2) now y<0 and x=|y| => y=-1 x=1 x+y>-1

y=-0.5 x=0.5 x+y>xy always since x+y=0 xy <0

IMO C

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cheers

Its Now Or Never