Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 May 2015, 03:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is x(y + z) > 0? 1) xyz > 0 2) yz > 0

Author Message
TAGS:
Intern
Joined: 19 Jul 2004
Posts: 2
Followers: 0

Kudos [?]: 0 [0], given: 0

Is x(y + z) > 0? 1) xyz > 0 2) yz > 0 [#permalink]  28 Jul 2004, 01:58
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Is x(y + z) > 0?

1) xyz > 0
2) yz > 0
Manager
Joined: 19 Jul 2004
Posts: 75
Followers: 1

Kudos [?]: 0 [0], given: 0

E...

1) xyz > 0
2) yz > 0

from 2) ----- (y+z) can be negative/positive...
from 1) xyz > 0 implies that x can be positive when (y+z) is positive...
x can be negative when (y+z) is negative..

hence there can be no conclusion on x(y+z) > 0
_________________

To Strive, To Seek and Not to Yield

Manager
Joined: 16 Jan 2004
Posts: 65
Location: NJ
Followers: 1

Kudos [?]: 0 [0], given: 0

why not C

You said

from 2) ----- (y+z) can be negative/positive...
from 1) xyz > 0 implies that x can be positive when (y+z) is positive...
x can be negative when (y+z) is negative..

Which means that when (y+z) is negative then x is negative hence x(y+z)has to be positive > 0

When (y+z) positive then x is positive hence x(y+z) is postive. In both the cases x(y+z) is positive.

Where am I going wrong. My GMAT is in next couple of days oh god!!!
CIO
Joined: 09 Mar 2003
Posts: 464
Followers: 2

Kudos [?]: 34 [0], given: 0

hey pakoo,

one mistake. x can't be negative when y and z are both negative, because then the whole thing would be negative. in fact, when we look at them together, x is always positive. But we don't know if yz is neg or pos, so we can't answer it.

Similar topics Replies Last post
Similar
Topics:
If xyz>0, is x(y)^(2z)^3>0 1) y>0 2) x>0 1 27 Apr 2006, 19:21
If xyz>0, is (xy)^(2z)^3>0 1) y>0 2) x>0 7 27 Apr 2006, 19:17
If xyz>0, is xy^2z^3>0 1) y>0 2) x>0 7 26 Apr 2006, 02:43
If x>y>z, is xz>0? 1) xy<0 2) yz>0 5 19 Mar 2006, 06:02
Is XYZ > 0? 1) XY > 0 2) YZ> 0 3 07 Jan 2006, 15:13
Display posts from previous: Sort by