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Is x<y<z? 1) y-x<z-x 2) z-y<z-x

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Is x<y<z? 1) y-x<z-x 2) z-y<z-x [#permalink] New post 05 May 2006, 23:11
Is x<y<z?

1) y-x<z-x
2) z-y<z-x
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 [#permalink] New post 06 May 2006, 00:54
I) If you simplify, it becomes: y < z

II) Simplify here and then multiply by -1 and switch the direction of the sign and you have y > x

Taken together, the answer is C.
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 [#permalink] New post 06 May 2006, 17:54
Agree with C :wink:
  [#permalink] 06 May 2006, 17:54
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