Is xy<0 ? 1) 1/x<1/y 2) x>0 : DS Archive
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# Is xy<0 ? 1) 1/x<1/y 2) x>0

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Is xy<0 ? 1) 1/x<1/y 2) x>0 [#permalink]

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18 May 2005, 13:16
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Is xy<0 ?

1) 1/x<1/y
2) x>0
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Joined: 15 Mar 2005
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18 May 2005, 13:21
A. 1/x < 1/y => x < y.
Both x and y could be positive, or one of them could be -ve. Thus insufficient.

B. x > 0. y could be > 0 or < 0. Insufficient.

Combine A and B.

x is +ve. Thus, 1/x is +ve too. Since 1/y > 1/x, 1/y is positive too. Therefore y is positive too. Sufficient.

C.
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Re: DS   [#permalink] 18 May 2005, 13:21
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# Is xy<0 ? 1) 1/x<1/y 2) x>0

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