sushma0805 wrote:

Is xy < 6 ?

a.x < 3 and y < 2.

b.1/2 < x < 2/3 and y^2 < 64.

source :

OG10.

I think the answer is B "Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked".

Option 1:

From this statement, X & Y can be -ve or +ve.

X=2, Y=1; XY=2 < 6

X=-2, Y=-5; XY=10 > 6

so, Not Sufficient

Option 2:

Here we know that X is +ve, but Y still can be -ve or +ve

when Y is -ve; XY is always -ve & < 6

when Y is +ve;

lets consider X=

\frac{2}{3}, Y=8, XY=

\frac{16}{3} = 5.333

so the maximum value of XY is < 5.333 <6

So, Sufficient

let me know if you need any more explanation or if you feel any thing is wrong

-Ravi