I think it's C....Alpha, you're right. I forgot to think about negatives. I thought of fractions, but not negatives.

My first thought is that we need to know if x and y are fractions. If only one is a fraction, it's not enough to answer the question with certainty.

(1) Is Insufficient because we know that \(x = \sqrt{\frac{3}{14}}\) but that doesn't tell us if Y is a fraction or not (or 1 as we'll see with statement 2)

(2) Insufficient because we know y = 1, we don't know the value of x.

x could be 10 so then we'd have (1)(10) > (10^2)(1^2) = 10 > 100...not true or x could be 1/2 so (1/2)(1) > (1/4)(1) = 1/2 > 1/4 true. Since we can answer yes or no, it is insufficient.

Together, if we know that \(x = \sqrt{\frac{3}{14}}\) and y = 1, then \(xy > x^2y^2\) always.

EDIT: Correct statement is \(x = +/-\sqrt{\frac{3}{14}}\)

pmenon wrote:

Is xy > \(x^2y^2\)?

(1) \(14x^2 = 3\)

(2) \(y^2 = 1\)

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J Allen Morris

**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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