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[quote="Balvinder"]Is xy > x/y?
(1) xy > 0
(2) y <0>x/y. If x=2, y=1/3, xy<x/y. INSUFF.
(2) y being negative in this case doesn't really tell you much and the sign is irrelevant. INSUFF.
Taking the two statements together we know that y is negative, so x must also be negative. But again, the signs of x & y are irrelevant. We need to know whether one of these is a fraction. So the answer is E.
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