Is z an integer? (1) z/3 is an integer. (2) z/2 is NOT an integer.

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
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The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

Since we have 1 variable (z) and 0 equations, D is most likely to be the answer. So, we should consider each condition on its own first.

Condition 1)

We have z = 3k for some integer k.
Then z is an integer.
Thus, the answer is 'yes'.

Since condition 1) yields a unique solution, it is sufficient

Condition 2)

If z = 1, then z/2 is not a integer, z is an integer and the answer is 'yes'.
If z = 1/2, then z/2 is not a integer, z is not an integer and the answer is 'no'.

Since condition 2) does not yield a unique solution, it is not sufficient


Therefore, A is the answer.

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.

Statement-1
z/3=int k
z = 3*k
product of two ints must be a int.
Sufficient

Statement-2
z/2=decimal d
z = 2*d
z may or may not be an int
d=1.5, 1.5*2 = 3 (int)
d=1.2, 1.2*2 = 2.4(deci)
Insufficient

OA <- A