Is z an odd integer?

We can solve this one easily by picking numbes.

Statement 1: if we could fine one odd and one even integer, both divisible by 3, we could show that this statement is insufficient. 3 and 6 are such numbers. To prove it by using number properties, we can just write 3as 1*3 and 6 as 2*3. As 3 is odd, multiplying it with odd and even numbers will have odd and even results. Insufficient.

Statement 2: With the same approach, we can show that the second statement is also insufficient. We just need to square 3 and 6. As 3is odd, it's square,9, must also be odd. As 6 can be written as 2*3, it's square is \((2*3)^2=2^2*3^3=36\), it must be even. Therefore statement 2is also insufficient.

Both taken together: as we see from the factorization, the numbers picked for statement 2 (9 and 36) already fulfill both statements and still do not allow a clear conclusion whether z is odd or even. Answer E.