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Is z+z<z? 1) -4z>4z 2) z^3<z^2

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Is z+z<z? 1) -4z>4z 2) z^3<z^2 [#permalink]

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New post 18 Oct 2006, 13:26
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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Is z+z<z?

1) -4z>4z
2) z^3<z^2
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New post 18 Oct 2006, 13:45
Is z+z<z?

1) -4z>4z
2) z^3<z^2

IS Z>Z/2 NOT TRUE ONLY IF Z IS NEGATIVE

FROM ONE

-Z>Z THUS Z IS NEGATIVE ...SUFF

FROM TWO

Z IS NEGATIVE > OR <1 OR A POSITIVE FRACTION

i SAY A

Last edited by yezz on 18 Oct 2006, 14:45, edited 2 times in total.
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New post 18 Oct 2006, 14:25
I think it is A.

z + z < z is possible for all negative - integers and fractions

From 1) we get z is negative

From 2) Not suff
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Re: DS: Integers [#permalink]

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New post 18 Oct 2006, 14:41
netcaesar wrote:
Is z+z<z?

1) -4z>4z
2) z^3<z^2



A

question : is z < 0 ?

from 1) 0 > 8z or z < 0 hence sufficient

from 2) z could be either negative or positive ( 0 < z < 1)
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Re: DS: Integers [#permalink]

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New post 18 Oct 2006, 19:03
netcaesar wrote:
Is z+z<z?

1) -4z>4z
2) z^3<z^2


A

2z<z only if z is -ve.

Statement 1: z is negative SUFF

Statement 2: 0<z<1, or z<0 INSUFF
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New post 31 Oct 2006, 08:34
Late but A for me as well.

Statement 2 could be a fraction or a negative number.
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  [#permalink] 31 Oct 2006, 08:34
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Is z+z<z? 1) -4z>4z 2) z^3<z^2

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