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It is the geometry again. There is a quadrilateral with

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It is the geometry again. There is a quadrilateral with [#permalink] New post 01 Apr 2004, 09:54
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It is the geometry again. There is a quadrilateral with sides, x, x, x+60 and 3x which forms a walking path. What is the total distance around the path?

1. One of the sides of the path is 120 meters long.
2. One of the sides of the path is twice as long as each of the two shortest sides.

I thought I got this right but official answer was different than what I got.
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answer [#permalink] New post 01 Apr 2004, 12:41
Official answer is B. Could you please elaborate.
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 [#permalink] New post 01 Apr 2004, 13:20
Ok...I'll try....: From Stem 2, we see that of the given sides x is the least side. Hence either x+60 = 2*x or 3x=2*x; Latter case doesnt make sense...hence go with x+60 =2x, which yields x = 60 and hence other sides can be found..........This is what I thought......wotsay others??
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Re: DS - Quadrilateral [#permalink] New post 03 Apr 2004, 03:30
statement 2 says => One of the sides of the path is twice as long as each of the two shortest sides

inference => shortest side is x, therefore one of the remaining two sides must be equal to 2x. given the sides are x, x, x+60 and 3x which leaves us equating x+60 = 2x

hence total distance = x + x + (x+60) + 3x => x + x + (2x) + 3x = 7x.

hence B
Re: DS - Quadrilateral   [#permalink] 03 Apr 2004, 03:30
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It is the geometry again. There is a quadrilateral with

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