|
Author |
Message |
|
TAGS:
|
|
|
Intern
Joined: 26 Jan 2004
Posts: 42
Location: US
Followers: 1
Kudos [?]:
0
[0], given: 0
|
It is the geometry again. There is a quadrilateral with [#permalink]
 01 Apr 2004, 10:54
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
It is the geometry again. There is a quadrilateral with sides, x, x, x+60 and 3x which forms a walking path. What is the total distance around the path?
1. One of the sides of the path is 120 meters long.
2. One of the sides of the path is twice as long as each of the two shortest sides.
I thought I got this right but official answer was different than what I got.
|
|
|
|
|
|
|
Intern
Joined: 26 Jan 2004
Posts: 42
Location: US
Followers: 1
Kudos [?]:
0
[0], given: 0
|
Official answer is B. Could you please elaborate.
|
|
|
|
|
|
Senior Manager
Joined: 05 Feb 2004
Posts: 417
Location: USA
Followers: 1
Kudos [?]:
1
[0], given: 0
|
Ok...I'll try....: From Stem 2, we see that of the given sides x is the least side. Hence either x+60 = 2*x or 3x=2*x; Latter case doesnt make sense...hence go with x+60 =2x, which yields x = 60 and hence other sides can be found..........This is what I thought......wotsay others??
|
|
|
|
|
|
Intern
Joined: 27 Mar 2004
Posts: 4
Followers: 0
Kudos [?]:
0
[0], given: 0
|
Re: DS - Quadrilateral [#permalink]
03 Apr 2004, 04:30
statement 2 says => One of the sides of the path is twice as long as each of the two shortest sides
inference => shortest side is x, therefore one of the remaining two sides must be equal to 2x. given the sides are x, x, x+60 and 3x which leaves us equating x+60 = 2x
hence total distance = x + x + (x+60) + 3x => x + x + (2x) + 3x = 7x.
hence B
|
|
|
|
|
|
|
Re: DS - Quadrilateral
[#permalink]
03 Apr 2004, 04:30
|
|
|
|
|
|
|
|
|
|
|
close
