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It takes 6 days for 3 women and 2 men working together to [#permalink]
12 Mar 2010, 22:33

2

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4

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00:00

A

B

C

D

E

Difficulty:

95% (hard)

Question Stats:

43% (03:27) correct
57% (02:29) wrong based on 79 sessions

It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Re: Interesting Work Problem [#permalink]
13 Mar 2010, 02:17

6

This post received KUDOS

Expert's post

2

This post was BOOKMARKED

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) days and one man in \(m\) days.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Re: Interesting Work Problem [#permalink]
13 Mar 2010, 02:22

2

This post received KUDOS

Answer is D. This is my explanation:

Let 9W take x days. Question gives us that 3M take x-5 days.

Therefore 1W does 1/9x of work in 1 day. ------> A 1M does 1/3(x-5) of work in 1 day. ------> B

We need to find what the above values in bold are to measure output. Hence we need to find x.

Using A and B 2M do 2/3(x-5) work in 1 day. 3W do 3/9x work in 1 day.

Therefore (2M + 3W) do 2/3(x-5) + 3/9x work in 1 day.

The above amount is 1/6th of work (Question says that 2M + 3W finish work in 6 days). 2/3(x-5) + 3/9x = 1/6 --------> Solve this to get x = 1 or x = 10. Take x=10 because x=1 cannot be substituted in B.

Substitute x=10 in A and B we get 1W does 1/90 work in 1 day => 1W does the work in 90 days. 1M does 1/15 work in 1 day => 1M does the work in 15 days.

1M does work 6 times (90/15) faster than 1W which implies 1M's output is 6 times that of 1W.

Re: Interesting Work Problem [#permalink]
13 Mar 2010, 02:56

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) hours and one man in \(m\) hours.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

But I think you have mixed days with hours. (w & m hours) _________________

Re: Interesting Work Problem [#permalink]
13 Mar 2010, 05:33

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Lets Try it working another smart way....

Let there be a total of 180 pages to be written (let it be the work that man and women and doing together and isolatedly. I have taken 180 for simplicity of calculations based on multiple of 6, 2, 3 and 9)

Now we have

3w+2m = 6 days

or 3w or 2m do 30 pages per day....(180pages/6days = 30 pages)

Now lets work with choices knowing that W or M can only be integers. (obviously Men or women can not be fraction numbers)

Only option 4 that gives 6 times can be solved as under

3w+2m= 30 pages

option 4 gives w=6m

so 3(6M) + 2m = 30

or m = 2

rest all options give fractional numbers for Men and women...

Hope this helps !!! correct me if i am wrong. Answer D... _________________

Re: Interesting Work Problem [#permalink]
03 Aug 2013, 11:30

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) hours and one man in \(m\) hours.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

I mess up in the reciprocals. I mean I did almost the exact same way as you except that I didn't switch the reciprocals. When I formulated the second condition, I did, 3/m = 9/w - 5. Can you please explain, when do we do what? Why are they both different? I kept the same fraction format for both conditions and didn't get the correct answer.

Re: Interesting Work Problem [#permalink]
27 Sep 2013, 04:42

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) hours and one man in \(m\) hours.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

Bunuel, Shouldn't we be writting

m/3 * (t-5) = w/9 * t where t is the time that women do the job.

Re: Interesting Work Problem [#permalink]
27 Sep 2013, 07:49

Expert's post

Skag55 wrote:

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) hours and one man in \(m\) hours.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

Bunuel, Shouldn't we be writting

m/3 * (t-5) = w/9 * t where t is the time that women do the job.

m/3 is time, t-5 is also time...

One man completes the job in \(m\) days --> 3 men in m/3 days. One woman completes the job in \(w\) days --> 9 women in w/9 days.

We are told that m/3 is 5 less than w/9 --> \(\frac{m}{3}+5=\frac{w}{9}\).

Re: It takes 6 days for 3 women and 2 men working together to [#permalink]
27 Sep 2013, 22:36

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work. 3 men would do the same work 5 days sooner than 9 women. How many times does the output of a man exceed that of a woman?

A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

1. Let 1 woman do the job in w days and 1 man do the job in m days 2. In 1 day, 1 woman does 1/w of the job and 1 man does 1/m of the job 3. 3 women do 3/w of the job and 2 men do 2/m of the job in 1 day. 4. It is given that 3 women and 2 men do the job in 6 days or in 1 day they do 1/6 of the job. 5. Equating (3) and (4) we have, 3/w + 2/m = 1/6 6. Also 3 men to do the work takes m/3 days. 9 women to do the work takes w/9 days 7. It is given that 3 men do the job 5 days sooner than 9 women. 8. So, m/3 = w/9 - 5 9. Solving (5) and (8) we have m=15 and w=90

Re: Interesting Work Problem [#permalink]
19 Nov 2013, 05:33

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) days and one man in \(m\) days.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

Hi Bunuel

I have the two equations well set and ready to go but I'm having some trouble with the algebra Any tips to solve faster? What approach did you use? Combination?

Re: Interesting Work Problem [#permalink]
19 Nov 2013, 05:38

Expert's post

jlgdr wrote:

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) days and one man in \(m\) days.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

Hi Bunuel

I have the two equations well set and ready to go but I'm having some trouble with the algebra Any tips to solve faster? What approach did you use? Combination?

Re: Interesting Work Problem [#permalink]
19 Nov 2013, 09:24

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) days and one man in \(m\) days.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

I don't get these workrate problems at all, I've gotten all 50 or 60 that I've tried incorrect...can you explain why here: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\) you had the w & m in the denominator, and then here \(\frac{m}{3}+5=\frac{w}{9}\) it was in the numerator?? Every time I see that stuff it makes NO sense to me, it looks like people just arbitrarily decide to put the letters in the numerator or the denominator. In this case, you have the first equation being for work rate, with the letters being in the denominator, and then the second equation for the work rate the letters appear in the numerator. I just don't get it.

Also how did you solve? Did you just look for numbers that made sense? Seems like there'd be a ton of arithmetic to do in such a sort time span to solve otherwise.

Re: Interesting Work Problem [#permalink]
19 Nov 2013, 14:17

Expert's post

AccipiterQ wrote:

Bunuel wrote:

Hussain15 wrote:

It takes 6 days for 3 women and 2 men working together to complete a work.3 men would do the same work 5 days sooner than 9 women.How many times does the output of a man exceed that of a woman? A. 3 times B. 4 times C. 5 times D. 6 times E. 7 times

Please provide the reasoning with your answers.

Let one woman complete the job in \(w\) days and one man in \(m\) days.

It takes 6 days for 3 women and 2 men working together to complete a work --> sum the rates: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\).

3 men would do the same work 5 days sooner than 9 women --> \(\frac{m}{3}+5=\frac{w}{9}\)

Solving: \(m=15\) and \(w=90\). \(\frac{w}{m}=6\).

Answer: D.

I don't get these workrate problems at all, I've gotten all 50 or 60 that I've tried incorrect...can you explain why here: \(\frac{3}{w}+\frac{2}{m}=\frac{1}{6}\) you had the w & m in the denominator, and then here \(\frac{m}{3}+5=\frac{w}{9}\) it was in the numerator?? Every time I see that stuff it makes NO sense to me, it looks like people just arbitrarily decide to put the letters in the numerator or the denominator. In this case, you have the first equation being for work rate, with the letters being in the denominator, and then the second equation for the work rate the letters appear in the numerator. I just don't get it.

Also how did you solve? Did you just look for numbers that made sense? Seems like there'd be a ton of arithmetic to do in such a sort time span to solve otherwise.

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