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It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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07 Aug 2008, 21:31

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It takes Computer A 36 hours to process data. If Computer A starts working at 7 pm on Monday and after half the data are processed Computer B, three times as fast as Computer A, joins in the task, when will the data processing be finished?

A. 4:30 pm Tuesday B. 5:30 pm Tuesday C. 7:00 pm Tuesday D. 8:30 pm Tuesday E. 10:30 pm Tuesday

Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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07 Aug 2008, 21:40

mba9now wrote:

It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?

comp A starts at 7pm on monday, processes half the data so it finishes at 7pm+(36/2)h which is 1pm on tuesday. Comp B takes up the next half so it finishes at 1pm+(12/2)h=7pm on Tuesday
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Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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08 Aug 2008, 07:42

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mba9now wrote:

It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?

Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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08 Aug 2008, 20:17

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mba9now wrote:

It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?

work done by A in one hr = w/36 by B in 1 hr=w/12 by both in 1 hr=w/12 + w/36=w/9

hence half the work is already done by A in 18 hrs

half the work w/2 is to be done by both hence time talken is w/2/w/9=9/2=4.5 hrs total time taken is 18+4.5 hrs=22.5 hrs 5.30pm tues is answer IMO B
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Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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08 Aug 2008, 22:07

mba9now wrote:

It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?

Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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09 Nov 2014, 11:29

Hello from the GMAT Club BumpBot!

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It takes Computer A 36 hours to process data. If Computer A starts working at 7 pm on Monday and after half the data are processed Computer B, three times as fast as Computer A, joins in the task, when will the data processing be finished?

A. 4:30 pm Tuesday B. 5:30 pm Tuesday C. 7:00 pm Tuesday D. 8:30 pm Tuesday E. 10:30 pm Tuesday

Computer A will process the first half of the data in 18 hours. Computer A and Computer B working together will process the remaining half four times quicker than will Computer A working alone. The entire task will require \(18 + \frac{18}{4} = 22.5\) hours which is 1.5 hours short of the 24-hour cycle. If the processing commences at 7 pm on Monday, it will finish at 5:30 pm on Tuesday.

Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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20 Nov 2015, 13:22

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: It takes Computer A 36 hours to process data. If Computer A starts wor [#permalink]

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20 Dec 2015, 21:20

x2suresh wrote:

mba9now wrote:

It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?

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