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# It takes printer A 4 more minutes than printer B to print 40

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Math Expert
Joined: 02 Sep 2009
Posts: 29802
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Kudos [?]: 53643 [0], given: 8167

Re: a good one [#permalink]  18 Feb 2014, 23:34
Expert's post
prasannajeet wrote:
Hi Bunuel

I may be crazy but let me understand what is wrong in the following equation and why I am not getting the right answer...
Lets rate of B=T so A=T+4

(1/T+4)+(1/T)=5/24....?????

Rgds
prasannajeet

If T is the rate how is T + (4 days) = (rate) + (time) = (rate) ???
If T is rate, then 1/T = 1/(rate) = (time), while 5/24 = (rate). How is (1/T+4)+(1/T) = (time) + (time) + (time) = 5/24 = (rate)???
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Manager
Joined: 26 Feb 2012
Posts: 117
Location: India
Concentration: General Management, Finance
WE: Engineering (Telecommunications)
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Kudos [?]: 13 [0], given: 56

Re: a good one [#permalink]  19 Feb 2014, 01:51
Bunuel wrote:
prasannajeet wrote:
Hi Bunuel

I may be crazy but let me understand what is wrong in the following equation and why I am not getting the right answer...
Lets rate of B=T so A=T+4

(1/T+4)+(1/T)=5/24....?????

Rgds
prasannajeet

If T is the rate how is T + (4 days) = (rate) + (time) = (rate) ???
If T is rate, then 1/T = 1/(rate) = (time), while 5/24 = (rate). How is (1/T+4)+(1/T) = (time) + (time) + (time) = 5/24 = (rate)???

Sorry for typo...
T is the time taken by B then T+4 is time taken by A.
So now the rate would be
40/T+40/T+4=50/6....Still wont get the right answer...

Pls Help.....

Rgds
Prasannajeet
Math Expert
Joined: 02 Sep 2009
Posts: 29802
Followers: 4904

Kudos [?]: 53643 [0], given: 8167

Re: a good one [#permalink]  19 Feb 2014, 02:36
Expert's post
prasannajeet wrote:
Bunuel wrote:
prasannajeet wrote:
Hi Bunuel

I may be crazy but let me understand what is wrong in the following equation and why I am not getting the right answer...
Lets rate of B=T so A=T+4

(1/T+4)+(1/T)=5/24....?????

Rgds
prasannajeet

If T is the rate how is T + (4 days) = (rate) + (time) = (rate) ???
If T is rate, then 1/T = 1/(rate) = (time), while 5/24 = (rate). How is (1/T+4)+(1/T) = (time) + (time) + (time) = 5/24 = (rate)???

Sorry for typo...
T is the time taken by B then T+4 is time taken by A.
So now the rate would be
40/T+40/(T+4)=50/6....Still wont get the right answer...

Pls Help.....

Rgds
Prasannajeet

Solving 40/T+40/(T+4)=50/6 gives T=8 minutes, thus printer A to print 40 pages takes T+4=12 minutes. The same answer as we have here: it-takes-printer-a-4-more-minutes-than-printer-b-to-print-98479.html#p759109

Hope it's clear.
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Concentration: General Management, Finance
Schools: HBS '16, Wharton '16
GMAT Date: 04-25-2014
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Followers: 0

Kudos [?]: 13 [1] , given: 13

Re: a good one [#permalink]  19 Feb 2014, 03:05
1
KUDOS
Nothing's wrong here. Your equation: [{1/(T+4)} + {1/T}] = 5/24 is a simplified version of the actual equation: $$6*[{40/(T+4)}+{40/T}]=50$$.

Which essentially has come from (what has been explained in above posts); i.e. In 1 minute, A can print 40/T+4 pages and B can print 40/T pages, so together in 1 min they can print 40/(T+4) + 40/T pages. Therefore, in 6 minutes, they can print 6*[{40/(T+4)}+{40/T}], which is given to be 50. When you simplify, you get the equation that you have written.

Pardon the repetitions or my lack of brevity

prasannajeet wrote:

Hi Bunuel

I may be crazy but let me understand what is wrong in the following equation and why I am not getting the right answer...
Lets rate of B=T so A=T+4

(1/T+4)+(1/T)=5/24....?????

Rgds
prasannajeet
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 6783
Followers: 367

Kudos [?]: 83 [0], given: 0

Re: It takes printer A 4 more minutes than printer B to print 40 [#permalink]  04 Apr 2015, 14:12
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Re: It takes printer A 4 more minutes than printer B to print 40   [#permalink] 04 Apr 2015, 14:12

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