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It would take Computer A 36 hours to process the data. If

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It would take Computer A 36 hours to process the data. If [#permalink] New post 07 Aug 2008, 21:31
It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?


4:30 pm Tuesday
5:30 pm Tuesday
7:00 pm Tuesday
8:30 pm Tuesday
10:30 pm Tuesday
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Re: PR- Computer [#permalink] New post 07 Aug 2008, 21:40
mba9now wrote:
It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?


4:30 pm Tuesday
5:30 pm Tuesday
7:00 pm Tuesday
8:30 pm Tuesday
10:30 pm Tuesday


comp A takes 36h and comp B takes 12h

comp A starts at 7pm on monday, processes half the data so it finishes at 7pm+(36/2)h which is 1pm on tuesday. Comp B takes up the next half so it finishes at 1pm+(12/2)h=7pm on Tuesday
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Re: PR- Computer [#permalink] New post 07 Aug 2008, 21:54
The answer is B (5:30 PM Tuesday). Becasue it is said that Comp B joins A, never says only B did the work alone.
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Re: PR- Computer [#permalink] New post 08 Aug 2008, 07:42
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mba9now wrote:
It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?


4:30 pm Tuesday
5:30 pm Tuesday
7:00 pm Tuesday
8:30 pm Tuesday
10:30 pm Tuesday


computer A take 36 hr
computer B takes 12 hr

18 hrs (half job done by computer) + Half job dont by both
= 18 hrs + 18 / (3+1) = 22.5 hrs.

B is the answer
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Re: PR- Computer [#permalink] New post 08 Aug 2008, 20:17
mba9now wrote:
It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?


4:30 pm Tuesday
5:30 pm Tuesday
7:00 pm Tuesday
8:30 pm Tuesday
10:30 pm Tuesday


work done by A in one hr = w/36
by B in 1 hr=w/12
by both in 1 hr=w/12 + w/36=w/9

hence half the work is already done by A in 18 hrs

half the work w/2 is to be done by both hence time talken is w/2/w/9=9/2=4.5 hrs
total time taken is 18+4.5 hrs=22.5 hrs
5.30pm tues is answer
IMO B
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Re: PR- Computer [#permalink] New post 08 Aug 2008, 22:07
mba9now wrote:
It would take Computer A 36 hours to process the data. If Computer A starts working at 7 pm on Monday and after half the data is processed Computer B, three times as fast as Computer A, is joined in the task, when will the data processing be finished?


4:30 pm Tuesday
5:30 pm Tuesday
7:00 pm Tuesday
8:30 pm Tuesday
10:30 pm Tuesday


Total hrs = 18 + Hours required to do half job = 18 + (18*6)/24 = 22.5 hrs = 5:30pm Tue
Re: PR- Computer   [#permalink] 08 Aug 2008, 22:07
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